Question

我正在寻找一种方法来在条件满足后停止迭代正内循环。我想过使用“继续”，但它没有做我想要的。 “break”似乎打破了整个循环，包括外循环。

所以在我的代码中，一旦满足条件。我想停止迭代j，但我想再次开始迭代。谢谢，

for i in 0..<sortedArray.count{
        for j in 1..<sortedArray.count{
            if sortedArray[j] == sortedArray[i]{
                //I want to skip iterating inner loop j from now. and back to iterating i
            }
        }
}

Answer 1

Break只会破坏内循环。

e.g。

for var i in 0...2
{
    for var j in 10...15
    {
        print("i = \(i) & j = \(j)")
        if j == 12
        {
            break;
        }
    }
}

输出 - ＆gt;

i = 0 & j = 10
i = 0 & j = 11
i = 0 & j = 12
i = 1 & j = 10
i = 1 & j = 11
i = 1 & j = 12
i = 2 & j = 10
i = 2 & j = 11
i = 2 & j = 12

Answer 2

嵌套索引循环和通过索引方法（let sortedArray = [2, 5, 7, 9] for i in sortedArray { for j in sortedArray where j <= i { print(j) } print("-----") } /* 2 ----- 2 5 ----- 2 5 7 ----- 2 5 7 9 ----- */）进行的后续元素访问是一种C ++'ish而不是Swifty。根据您的应用程序，您可以充分利用Swift中的简洁功能来实现您的目标。

例如，假设（基于数组的anme）对数组进行排序，

for ... in (... where ...)

请注意，我们不关心上面数组的索引，而是直接在for i in 1...sortedArray.count { sortedArray.prefixUpTo(i).forEach { print($0) } print("-----") } /* same printout as above */循环中访问数组的元素。

另一个替代coulkd使用prefixUpTo(:_)

 $servername = "localhost";  //host name

 $username = "username"; //username

 $password = "password"; //password

 $database = "dbname"; //database name

//mysqli prepared statement 

$conn = mysqli_connect($servername, $username, $password) or die("Connection failed: " . mysqli_connect_error());

mysqli_select_db($conn,$database) or die("Opps some thing went wrong");
$Wn8overall = mysqli_real_escape_string($_POST['wn8overall']);
$Wn8recent = mysqli_real_escape_string($_POST['wn8recent']);
$Email = mysqli_real_escape_string($_POST['email']);
$Zileonline = mysqli_real_escape_string($_POST['zileonline']);
$Tara = mysqli_real_escape_string($_POST['tara']);
$Tank10 = mysqli_real_escape_string($_POST['tank10']);
$Tank8 = mysqli_real_escape_string($_POST['tank8]);
$Careclan = mysqli_real_escape_string($_POST['careclan']);
$Numecont = mysqli_real_escape_string($_POST['numecont']);

$stmt = $conn->prepare("INSERT INTO aplicatii1 (wn8overall,wn8recent,email,zileonline,tara,tank10,tank8,careclan,numecont)  VALUES (?,?,?,?,?,?,?,?,?)");

$stmt->bind_param('sssssssss',$Wn8overall,$Wn8recent,$Email,$Zileonline,$Tara,$Tank10,$Tank8,$Careclan$Numecont);
            /*
                The argument may be one of four types:

                            i - integer
                            d - double
                            s - string
                            b - BLOB
                            change it by respectively
            */ 
$stmt->execute();

$row_count= $stmt->affected_rows;

$stmt->close();
$conn->close();

 if($row_count>0){
    echo "New record created successfully";
 }
else{

}

如何在Swift中打破/逃避内循环

2 个答案: