Question

这是一张表：

mysql> SELECT * FROM test_member order by points asc;
+-----------+---------+
| member_id | points  |
+-----------+---------+
|        34 |    1000 |
|        22 |    2000 |
|        33 |    2000 |
|        35 |    3000 |
+-----------+---------+

正确的结果：当我的member_id是＆＃39; 35＆＃39;时，我的排名将是＆＃39; 1＆＃39;，

当我的member_id为＆＃39; 22＆＃39;时，我的排名将为＆＃39; 2＆＃39;

当我的member_id为＆＃39; 33＆＃39;时，我的排名将为＆＃39; 2＆＃39;

当我的member_id是＆＃39; 34＆＃39;时，我的排名将是＆＃39; 3＆＃39;

...

等等。

尝试 - 1

SELECT * FROM (
SELECT    member_id,
          @points := @points + 1 AS rank
FROM      test_member p, (SELECT @points := 0) r
ORDER BY  points DESC
  ) t
WHERE member_id='33';

+-----------+----------------------------------------+
| member_id | rank                                   |
+-----------+------------+------+---------+----------+
|     33    | 3.000000000000000000000000000000       |
+-----------+----------------------------------------+

尝试 - 2（mysql + php方式）

<?php
$simulation_ponits = 1000;

$sql = '
  SELECT t.points, COUNT(*) as count_num
  FROM test_member as t
  WHERE t.points > ' . $simulation_ponits . ' 
  GROUP BY t.points
  HAVING t.points > ' . $simulation_ponits .' 
';

$result = mysql_query($sql);

$count_rank = 1;
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
    $count_rank +=$row['count_num'];
}


+--------+-----------+
| points | count_num |
+--------+-----------+
|   2000 |         2 |
|   3000 |         1 |
+--------+-----------+


# $count_rank => 3

两次尝试都只有mysql + php方式才能显示正确的结果，我可以通过其他方式尝试这样做吗？提前谢谢。

Answer 1

您正在尝试获得排名，而不是行号。以下应该有效：

SELECT * FROM (
  SELECT    member_id,
            @rnk := @rnk + if (@prevPoints = points, 0,
                       if (@prevPoints := points, 1, 1)) as rnk
  FROM      test_member p, (SELECT @rnk := 0, @prevPoints := null) r
  ORDER BY  points DESC
) t
WHERE member_id = 33

SQL Fiddle Demo

mysql-在分数中获得与其他人相比的自我排名

1 个答案: