Question

这是在SQL Server中。我正在寻找一种方法来添加一列来从201602中减去201601列。

IE如果在程序运行后，201601的tranamt为10,000，而201602的tranamt为11,000，我想要一个将产生1,000的列出现在这两列的旁边。

这适用于数千行，因此无法使用括号。

我在where子句之后尝试了一个subselect，它甚至没有出现，甚至远远接近正确，并使我的枢轴没有返回任何东西，好像它被否定了。我有大约一个月的SQL经验。

SELECT *


FROM (
SELECT  c.BLDGID AS 'BLDGID', 
        c.LEASID AS 'LEASID', 
        l.OCCPNAME AS 'OCCPNAME', 
        l.SUITID AS 'SUITID', 
        c.INCCAT AS 'INCCAT', 
        c.SRCCODE AS 'SRCCODE', 
        c.TRANAMT AS 'TRANAMT', 
        c.PERIOD AS 'PERIOD'
FROM SQLDATA.dbo.LEAS l
INNER JOIN SQLDATA.dbo.CMLEDG c
    ON l.BLDGID = c.BLDGID AND l.LEASID = c.LEASID
WHERE  c.BLDGID 87000
    AND c.INCCAT JYL
    AND c.SRCCODE NOT LIKE 'CR'
    AND c.SRCCODE NOT LIKE 'PR'
    AND DESCRPTN NOT LIKE 'SECURITY APPLIED'


    AND c.PERIOD BETWEEN 201601 and 201602

) as t
PIVOT (
SUM(TRANAMT) 
FOR PERIOD IN ([201601],[201602])




) revenueperspace

ORDER BY BLDGID, SUITID

Answer 1

在SELECT *中，您可以将其更改为

SELECT *, revenueperspace.[201602]-revenueperspace.[201601] as Diff

在具有数据透视的SQL中添加差异或总和列？

1 个答案: