Question

input = [ {"name" => "adam",  "nick" => ["kuruvi", "cali"] },
          {"name" => "eve",   "nick" => ["cali"]           },
          {"name" => "enoch", "nick" => []                 },    
          {"name" => "ebe",   "nick" => ["test", "wrong"]  },
          {"name" => "fred",  "nick" => ["da"]             } ]

我想选择包含"da"＆amp;的哈希值"cali"中的"nick"。

input.select do |d|
  d["nick"].include?("cali")
end

给出

[{"name"=>"adam", "nick"=>["kuruvi", "cali"]},
 {"name"=>"eve", "nick"=>["cali"]}]

我们如何检查两个参数。例如：include?("cali","da")以便我的结果

 [{"name"=>"adam", "nick"=>["kuruvi", "cali"]},
  {"name"=>"eve", "nick"=>["cali"]},
  {"name" => "fred",  "nick" => ["da"]}]

试过这个

 i = ["da","cali"]
 input.select do |d|
   d["nick"].all? { |v| i.include? v }
 end

=> [{"name" => "adam",  "nick" => ["kuruvi", "cali"]},
    {"name" => "eve",   "nick" => ["cali"]},
    {"name" => "enoch", "nick" => []},
    {"name" => "fred",  "nick" => ["da"]}]

（但这会返回带"nick"=[]的哈希值）

Answer 1

根据您想要的结果，您指的是＆＃34;或＆＃34;，而不是＆＃34;和＆＃34;。以下使用方法Array#&。

input.reject { |h| (h["nick"] & ["cali", "da"]).empty? }
  #=> [{"name"=>"adam", "nick"=>["kuruvi", "cali"]},
  #    {"name"=>"eve", "nick"=>["cali"]},
  #    {"name"=>"fred", "nick"=>["da"]}]

Answer 2

您需要进行两项不同的include?测试：

l = d['nick']
l.include?('da') && l.include?('cali')

您也可以尝试：

(d['nick'] & %w[ da cali ]).length == 2

或者，如果你想要，你可以编写自己的方法来测试重叠，或者甚至将它修补为数组include_all?

Answer 3

您可以使用all?来获得所需的结果，而不是使用any?。

input.select do |d|
  d["nick"].any? { |h| ['cali','da'].include?(h) }
end

返回

[{"name"=>"adam", "nick"=>["kuruvi", "cali"]}, 
 {"name"=>"eve",  "nick"=>["cali"]}, 
 {"name"=>"fred", "nick"=>["da"]}]

使用“AND”操作从ruby中的哈希数组中选择哈希值

3 个答案: