在matplot3D中更改标签的字体大小

Question

我的代码如下：

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在2D版本中工作的fig = plt.figure() ax = fig.add_subplot(111, projection='3d') ax.scatter(xs, ys, zs, c='r', marker='o',label='A') ax.scatter(x, y, z, c='b', marker='^',label='B') ax.set_xlabel('X') ax.set_ylabel('Y') ax.set_zlabel('Z') ax.tick_params(axis='both', which='major', labelsize=6) ax.tick_params(axis='both', which='minor', labelsize=6) plt.savefig(outfile) 无效。

我该怎么做？这篇文档非常难以理解。

请注意，这是轴标题的字体大小，而不是刻度标签。

Answer 1

问题中的代码运行正常。

ax.tick_params(..., labelsize=6)

可用于更改标签的字体大小。

完整的例子

import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D

x,y,z = zip(*np.random.rand(10,3))

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

ax.scatter(x, y, z, c='b', marker='^',label='B')

ax.set_xlabel('X')
ax.set_ylabel('Y')
ax.set_zlabel('Z')

ax.tick_params(axis='both', which='major', labelsize=6)
ax.tick_params(axis='both', which='minor', labelsize=6)

plt.show()

产生这个情节：