Question

我的日志是文本文件格式，看起来像这样

UID,      Provider,     MobileNo,      Result Time,        Outcome
443,        ABC,        65437261,   2016-08-09 23:59:59,     Pass
445,        ABC,        87658905,   2016-08-09 23:58:05,     Pass
023,        ABC,        87658905,   2016-08-09 21:58:05,     Pass
023,        ABC,        87658905,   2016-08-09 19:58:05,     Pass

我想知道如何创建一个读取文件并计算每小时事务数的批处理文件。

我希望我的结果如下：

2300Hrs 345 transactions
2200Hrs 2891 transactions
0700Hrs 8873 transactions

Answer 1

我不理解您的请求（＆＃34;每小时的交易次数＆＃34;是速度期限）。但是，如果您希望计算行中行的数量，那么这是一个解决方案：

@echo off
setlocal

rem Count transactions in the same hour
for /F "skip=1 tokens=5 delims=: " %%a in (theLogFile.txt) do set /A "trans[%%a]+=1"

rem Report them
for /F "tokens=2,3 delims=[]=" %%a in ('set trans[') do echo %%a00Hrs %%b transactions

具有给定数据的输出示例：

1900Hrs 1 transactions
2100Hrs 1 transactions
2300Hrs 2 transactions

Answer 2

...作为@Aacini优秀响应的延续，并预先阻止Provider和/或MobileNo字段中不可避免的空间，或许：

@Echo Off
SetLocal

Rem Count transactions in the same hour
For /F "Skip=1 Tokens=4 Delims=," %%a In (theLogFile.txt) Do (Set _=%%a
    Call Set/A "trans[%%_:~-8,2%%]+=1")

Rem Report them
For /F "Tokens=2,3 Delims=[]=" %%a In ('Set trans[') Do (
    Echo( %%a00Hrs %%b transaction(s^))
Timeout -1

使用批处理文件计算每小时的事务数

2 个答案: