现在onTouch
已经实现了一个不同的类。有两个类,一个是主要 CircleMActivity.java
,另一个是onTouch
。
现在该应用程序正常运行但有一个问题。当我点击按钮并移动它时它正在移动,但按钮和屏幕触摸之间存在间隙。
我想要的是将它移动到我触摸它的位置不稍后或者您可以认为我想要移动它确切的光标位置。 我应该如何实现它?
代码:
CircleMActivity.java:
public class CircleMActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_circle_m);
Button b=(Button)findViewById(R.id.btn1);
MultiTouch mtb=new MultiTouch(this);
b.setOnTouchListener(mtb);
}
}
MultiTouch.java :
public class MultiTouch implements OnTouchListener{
float mPrevX,mPrevY;
CircleMActivity cm;
public MultiTouch(CircleMActivity circleMActivity) {
// TODO Auto-generated constructor stub
cm=circleMActivity;
}
@Override
public boolean onTouch(View arg0, MotionEvent arg1) {
// TODO Auto-generated method stub
float currentX,currentY;
int action=arg1.getAction();
switch(action){
case MotionEvent.ACTION_DOWN:
mPrevX = arg1.getX();
mPrevY = arg1.getY();
break;
case MotionEvent.ACTION_MOVE:
currentX = arg1.getRawX();
currentY = arg1.getRawY();
MarginLayoutParams marginParams = new MarginLayoutParams( arg0.getLayoutParams());
marginParams.setMargins((int)( currentX - mPrevX), (int)( currentY - mPrevY),0, 0);
LayoutParams layoutParams = new LinearLayout.LayoutParams(marginParams);
arg0.setLayoutParams(layoutParams);
break;
case MotionEvent.ACTION_CANCEL:
break;
case MotionEvent.ACTION_UP:
break;
}
return true;
}
}
activity_circle.xml :
<LinearLayout
android:layout_height="match_parent"
android:layout_width="match_parent"
xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:background="#000000"
android:weightSum="100">
<LinearLayout
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:layout_weight="4.95"
android:background="#fff"
android:orientation="vertical" >
<EditText
android:id="@+id/editText1"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="X coord"
android:textColor="#ff00ee"
android:inputType="number" >
<requestFocus />
</EditText>
<EditText
android:id="@+id/editText2"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="Y coord"
android:textColor="#ff00ee"
android:inputType="number" />
<EditText
android:id="@+id/editText3"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="Radius"
android:textColor="#ff00ee"
android:inputType="number" />
<EditText
android:id="@+id/editText4"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:ems="10"
android:textColor="#ff00ee"
android:hint="Colour"
android:inputType="number" />
</LinearLayout>
<Button
android:id="@+id/btn1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_weight="4.95"
android:background="@drawable/custom" />
"
</LinearLayout>
那我该怎么做呢?
答案 0 :(得分:0)
这是一个简单的坐标数学。在你的
case MotionEvent.ACTION_DOWN:
mPrevX = arg1.getX();
mPrevY = arg1.getY();
break;
制作
mPrevY = arg1.getY()+250;
好吧它会离开孩子linear layout
,但看起来很棒!