Question

我有一个表格数据如下

day group   category    appcount
-----------------------------------------
Fri F27-28  music   4
Fri F27-28  radio   1
Fri F27-28  show    1
Fri F27-28  video   8
Fri F29-32  music   6
Fri F29-32  radio   2
Fri F29-32  video   22
Fri M22-    music   1
Fri M22-    video   2
Fri M23-26  music   4
Fri M23-26  video   8

现在，我希望通过旋转类别和日期获得结果，如下所示。

Age Group   music-Fri   music-Mon   music-Sun   music-Tue   music-Sat   music-Thu   music-Wed   radio-Fri   radio-Mon   radio-Sun   radio-Tues  radio-Sat   radio-Thu   radio-Wed
-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
F27-28  4   16  5   11  17  13  9   1   1   3   2   8   2   
F29-32  6       2   6   4   4   4   2   5       2       3   2
F33-42      2   2               3       1   1               3
M22-    1   15  14  10      4   4                           
M23-26  4   7   5   2   12  14  7

我尝试了一些查询但无法实现分组2列，日期和类别。对不起数据格式问题。请帮忙。

这是我的查询

SELECT *
FROM (
    SELECT 
        [group],
        [day],
        category, 
        appcount as counts 
    FROM monthly_age_apps
) as s
PIVOT
(
    SUM(counts)
    FOR [category] IN (video, radio, show, music)
)AS pvt

谢谢你，Sathish

Answer 1

我发现对许多数据透视查询使用条件聚合更简单：

Time: [object HTMLInputElement] will...

Answer 2

对于ANSI-Sql，您可以使用条件聚合：

SELECT t.group , 
       MAX(CASE WHEN t.day = 'Sun' AND t.category = 'music' AND THEN t.appcount) as Sun-Music,
       MAX(CASE WHEN t.day = 'Sun' AND t.category = 'radio' AND THEN t.appcount) as Sun-Radio,
       MAX(CASE WHEN t.day = 'Mon' AND t.category = 'music' AND THEN t.appcount) as Mon-Music,
       MAX(CASE WHEN t.day = 'Mon' AND t.category = 'radio' AND THEN t.appcount) as Mon-Radio,
       ........
FROM YourTable t
GROUP BY t.group

具有多列分组的SQL Pivot查询

2 个答案: