Question

我有一个像下面这样的SQL查询，

SELECT patient.*,
contact.telephone
from patient
INNER JOIN contact ON patient.`idPatient` = contact.`idPatient`

这些是我的作品，

Patient.hbm.xml

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<!-- Generated Sep 8, 2016 1:55:08 PM by Hibernate Tools 4.3.1 -->
<hibernate-mapping>
    <class name="db.Patient" table="patient" catalog="example_hibernate" optimistic-lock="version">
        <id name="idPatient" type="java.lang.Integer">
            <column name="idPatient" />
            <generator class="identity" />
        </id>
        <property name="title" type="string">
            <column name="title" length="45" />
        </property>
        <property name="firstName" type="string">
            <column name="firstName" length="45" />
        </property>
        <property name="lastName" type="string">
            <column name="lastName" length="45" />
        </property>
        <property name="middleName" type="string">
            <column name="middleName" length="45" />
        </property>
        <property name="dob" type="date">
            <column name="dob" length="10" />
        </property>
        <property name="martitalStatus" type="java.lang.Boolean">
            <column name="martitalStatus" />
        </property>
        <property name="gender" type="string">
            <column name="gender" length="45" />
        </property>
        <property name="nic" type="string">
            <column name="nic" length="45" />
        </property>
        <property name="dateCreated" type="timestamp">
            <column name="dateCreated" length="19" />
        </property>
        <property name="lastUpdated" type="timestamp">
            <column name="lastUpdated" length="19" not-null="true" />
        </property>
        <set name="contacts" table="contact" inverse="true" lazy="true" fetch="select">
            <key>
                <column name="idPatient" not-null="true" />
            </key>
            <one-to-many class="db.Contact" />
        </set>
    </class>
</hibernate-mapping>

Contact.hbm.xml

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">
<!-- Generated Sep 8, 2016 1:55:08 PM by Hibernate Tools 4.3.1 -->
<hibernate-mapping>
    <class name="db.Contact" table="contact" catalog="example_hibernate" optimistic-lock="version">
        <id name="idContact" type="java.lang.Integer">
            <column name="idContact" />
            <generator class="identity" />
        </id>
        <many-to-one name="patient" class="db.Patient" fetch="select">
            <column name="idPatient" not-null="true" />
        </many-to-one>
        <property name="telephone" type="string">
            <column name="telephone" length="45" />
        </property>
        <property name="address" type="string">
            <column name="address" length="45" />
        </property>
    </class>
</hibernate-mapping>

然后我使用上面的sql，

SessionFactory sessionFactory = new HibernateUtil().getSessionFactory();
        Session session = sessionFactory.openSession();

        List<Object[]> africanContinents = session.createQuery(
                "SELECT patient.*,\n"
                + "contact.telephone\n"
                + "from patient\n"
                + "INNER JOIN contact ON patient.`idPatient` = contact.`idPatient`")
                .list();
HibernateUtil.shutdown();

但是这个例子让我失意

org.hibernate.QueryException: unexpected char: '`' [SELECT patient.*,
contact.telephone
from patient
INNER JOIN contact ON patient.`idPatient` = contact.`idPatient`]

我不知道如何处理这个异常。因为这个sql查询是正确的。对此例外有任何想法吗？

Answer 1

createQuery中的查询应该用HQL或JPQL编写。

因此，您可以在HQL中重写您的查询（例如，从患者内部加入联系人那里选择p，c.telephone＆＃39;）请参阅文档here

或者您可以通过调用session.createSQLQuery而不是session.createQuery

来使用SQL查询

希望这会有所帮助。的Sebastien

例外：在hibernate中使用内部联接

1 个答案: