Java:扫描程序在运行时无法识别

时间:2010-10-15 00:53:52

标签: java input

我是一年级学生,在学校学习二传手和吸气。 当我运行它时,它忽略了以下语句:

String Origin = scan.nextLine();

然后它转到下一行。

这是主要的:

import java.util.Scanner;

public class FlightTest
{
    public static void main (String [] args)
    {
        Scanner scan = new Scanner (System.in);
        Flight Flight1 = new Flight ();

        System.out.print ("Airline Name: ");
        String AirlineName = scan.nextLine ();

        System.out.print ("Flight Number: ");
        int FlightNumber = scan.nextInt ();

        System.out.print ("Origin: ");
        String Origin = scan.nextLine(); // There is a problem here

        System.out.print ("Destination: ");
        String Destination = scan.nextLine ();
    }   
}

这是班级

public class Flight
{
    private String AirlineName;

    private int FlightNumber;

    private String Origin;

    private String Destination;

    public String setAirlineName()
    {
        String Name = AirlineName;
        return Name;
    }

    public String getAirlineName()
    {
        return AirlineName;
    }

    public int setFlightNumber ()
    {
        int Number = FlightNumber;
        return Number;
    }

    public int getFlightNumber ()
    {
        return FlightNumber;
    }

    public String setOrigin ()
    {
        String Orig = Origin;
        return Orig;
    }

    public String getOrigin ()
    {
        return Origin;
    }

    public String setDestination ()
    {
        String Desti = Destination;
        return Desti;
    }

    public String getDestination ()
    {
        return Destination;
    }

    public String toString ()
    {
        String result = AirlineName + " flight number " 
                 + FlightNumber + " leaves from " + Origin + " to "
                 + Destination + ".";
        return result;
    }
}

2 个答案:

答案 0 :(得分:2)

因为scan.nextInt()不使用整行,下一次调用scan.nextLine()会返回航班号所在的行的末尾,这可能只是换行符。

再次致电scan.nextLine()

System.out.print ("Flight Number: ");
int FlightNumber = scan.nextInt ();
scan.nextLine(); // get rid of rest of line

System.out.print ("Origin: ");
String Origin = scan.nextLine();

我觉得事情会奏效。

答案 1 :(得分:0)

你的setter错了,你应该传递一个参数。

private String airlineName;
public String getAirlineName() {
    return airlineName;
}
public void setAirlineName(String airlineName) {
    this.airlineName = airlineName;
}

你可以像这样使用setter

Flight f = new Flight ();

System.out.print ("Airline Name: ");
f.setAirlineName(scan.nextLine ());