Question

我有一个长度未知的字符串，包含字符a-z A-Z 0-9。我需要使用字典从左到右更改每个字符。

示例：

string = "aaaaaaaa"
def shift_char(text):
    for i in len(text):
        # Do Something for each character
    return output
print shift_char(string)
'adktivep'

Answer 1

好吧，希望这是可以理解的，否则随意提问。

import random
import string

# Letter pool, these are all the possible characters
# you can have in your string
letter_pool = list(string.ascii_letters + string.digits)

input_string = "HelloWorld"
string_length = len(input_string)

# Generate one random dictionary for each character in string
dictionaries = []

for i in range(string_length):
    # Copy letter_pool to avoid overwriting letter_pool
    keys = list(letter_pool)
    values = list(letter_pool)
    # Randomise values, (keep keys the same)
    random.shuffle(values)

    # This line converts two lists into a dictionary
    scrambled_dict = dict(zip(keys, values))

    # Now each letter (key) maps to a random letter (value)
    dictionaries.append(scrambled_dict)

# Initiate a fresh string to start adding characters to
out_string = ""

# Loop though the loop string, record the current place (index) and character each loop
for index, char in enumerate(input_string):
    # Get the dictionary for this place in the string
    dictionary = dictionaries[i]
    # Get the randomised character from the dictionary
    new_char = dictionary[char]
    # Place the randomised character at the end of the string
    out_string += new_char

# Print out the random string
print(out_string)

编辑：如果您只想生成一次随机词典，并且每次都加载它们，您可以序列化dictionaries数组。我最喜欢的是json。

Answer 2

在Mark Tolonen的this post的帮助下，我能够找到解决方案。以下示例仅使用4个词典，而我打算执行更多操作：

# Input String
string = "ttttttttttttttttttttttttttttttt"

# Defining dictionarys for 0-4
dicnums = [{"0":"n","1":"Q","2":"k","3":"W","4":"F","5":"g","6":"9","7":"e","8":"v","9":"3","a":"r","b":"T","c":"c","d":"o","e":"b","f":"y","g":"2","h":"A","i":"i","j":"p","k":"1","l":"P","m":"w","n":"x","o":"s","p":"Y","q":"h","r":"G","s":"7","t":"S","u":"6","v":"K","w":"Z","x":"M","y":"C","z":"J","A":"u","B":"f","C":"j","D":"E","E":"a","F":"H","G":"O","H":"N","I":"l","J":"U","K":"I","L":"V","M":"m","N":"5","O":"R","P":"4","Q":"z","R":"L","S":"0","T":"q","U":"D","V":"8","W":"B","X":"X","Y":"d","Z":"t"}, {"0":"q","1":"6","2":"W","3":"4","4":"J","5":"u","6":"n","7":"T","8":"I","9":"O","a":"V","b":"3","c":"Z","d":"s","e":"R","f":"E","g":"G","h":"P","i":"5","j":"l","k":"e","l":"m","m":"F","n":"t","o":"8","p":"K","q":"L","r":"Y","s":"M","t":"D","u":"j","v":"z","w":"H","x":"g","y":"9","z":"f","A":"0","B":"p","C":"o","D":"d","E":"X","F":"S","G":"k","H":"1","I":"Q","J":"C","K":"U","L":"i","M":"r","N":"w","O":"y","P":"B","Q":"2","R":"x","S":"A","T":"c","U":"7","V":"h","W":"v","X":"N","Y":"b","Z":"a"}, {"0":"x","1":"W","2":"q","3":"B","4":"j","5":"I","6":"E","7":"g","8":"U","9":"e","a":"8","b":"3","c":"5","d":"k","e":"9","f":"N","g":"7","h":"Q","i":"t","j":"r","k":"L","l":"Z","m":"b","n":"n","o":"Y","p":"H","q":"R","r":"6","s":"P","t":"1","u":"S","v":"M","w":"p","x":"l","y":"F","z":"2","A":"c","B":"T","C":"G","D":"h","E":"X","F":"v","G":"s","H":"O","I":"D","J":"4","K":"a","L":"A","M":"m","N":"d","O":"C","P":"f","Q":"V","R":"i","S":"o","T":"u","U":"w","V":"0","W":"K","X":"z","Y":"y","Z":"J"}, {"0":"x","1":"W","2":"q","3":"B","4":"j","5":"I","6":"E","7":"g","8":"U","9":"e","a":"8","b":"3","c":"5","d":"k","e":"9","f":"N","g":"7","h":"Q","i":"t","j":"r","k":"L","l":"H","m":"b","n":"n","o":"Y","p":"Z","q":"R","r":"6","s":"P","t":"1","u":"S","v":"M","w":"p","x":"l","y":"F","z":"2","A":"c","B":"T","C":"G","D":"h","E":"X","F":"v","G":"s","H":"O","I":"D","J":"4","K":"a","L":"A","M":"m","N":"d","O":"C","P":"f","Q":"V","R":"i","S":"o","T":"u","U":"w","V":"0","W":"K","X":"z","Y":"y","Z":"J"}]

# Changing my string characters
string_fin = ''.join(dicnums[i%4][c] for i,c in enumerate(string))

# Print result
print string_fin

如果我使用全部't'，结果为"SD11SD11SD11SD11SD11SD11SD11SD1"。如果我使dict范围更宽，并且我没有重复使用相同的字符（我不会），那么输出会好得多。一旦与我的其余加密概念结合使用，我的程序可能实际上就像我想要的那样工作。

根据其位置改变角色？ Python 2.7

2 个答案: