是否有css3方法动态地使滑块点在对角线平面上倾斜?
https://jsfiddle.net/9dtgqw95/5/
span {
background: red;
width: 15px;
height: 15px;
border-radius: 15px;
display: inline-block;
margin-right: 5px;
}
span:nth-child(n) {
margin-top: 15px;
}

<div>
<span></span><span></span><span></span>
</div>
&#13;
如果容器被旋转 - 如果有更多的点
会有定位问题答案 0 :(得分:0)
你可以用绝对位置推动它
#include <string>
#include <vector>
#include <functional>
struct Task
{
std::string Name;
std::vector<Task*> *Subtasks;
std::function<void(std::string const &)> Job;
Task() {}
Task(std::string const &arg_0) { Name = arg_0; }
Task(std::string const &arg_0, std::vector<Task*> *arg_1) { Name = arg_0; Subtasks = arg_1; }
Task(std::string const &arg_0, std::function<void(std::string const &)> arg_1)
{ Name = arg_0; Job = arg_1; }
~Task() { for (auto tItem : *Subtasks) { delete tItem; } }
};
class Console
{
private:
std::vector<Task*> Routine;
public:
~Console() { for (auto tItem : Routine) { delete tItem; } } //I thought that this is not needed but Valgrind thinks otherwise, strangely the deconstructors of the Tasks are not called, I guess.
void add(Task *arg_0) { Routine.push_back(arg_0); }
void foo()
{
Task *tTask = new Task();
//Task *tTask = new Task("Name");
//Task *tTask = new Task("Name", [this](std::string const &arg_0){ ; });
//Seg. fault still remains.
add(tTask);
}
};
int main()
{
Console _Console;
_Console.foo();
}
div {position:relative;}
span {
background: red;
width: 15px;
height: 15px;
border-radius: 15px;
display: inline-block;
position: absolute;
top:0;
}
span:nth-child(2) {
top: 15px;
left: 15px;
}
span:nth-child(3) {
top: 30px;
left: 30px;
}
答案 1 :(得分:0)
您可以倾斜容器并以相反的方式扭曲点
div {
transform: skewY(45deg);
transform-origin: left top;
}
span {
transform: skewY(-45deg);
background: red;
width: 15px;
height: 15px;
border-radius: 15px;
display: inline-block;
margin-right: 5px;
}
span:nth-child(n) {
margin-top: 15px;
}
<div>
<span></span><span></span><span></span>
</div>