我无法使类符合使用associatedtype
的协议。在Playground中,我输入了一个简短而简单的例子来说明这个问题:一个产生ItemType
兼容项的生产者和一个消费它们的消费者。它如下:
protocol ItemType { }
protocol Producer: class {
associatedtype T: ItemType
func registerConsumer<C: Consumer where C.T == T>(consumer: C)
}
protocol Consumer: class {
associatedtype T: ItemType
func consume<P: Producer where P.T == T>(producer: P, item: T)
}
struct EmptyItem: ItemType { }
class DummyProducer: Producer {
var consumer: DummyConsumer?
func registerConsumer(consumer: DummyConsumer) {
self.consumer = consumer
}
}
class DummyConsumer: Consumer {
func consume(producer: DummyProducer, item: EmptyItem) {
print("Received \(item) from producer \(producer)")
}
}
Xcode警告我以下错误:
Playground execution failed: MyPlaygroundYeYe.playground:14:7: error: type 'DummyProducer' does not conform to protocol 'Producer'
class DummyProducer: Producer {
^
MyPlaygroundYeYe.playground:3:20: note: protocol requires nested type 'T'
associatedtype T: ItemType
^
MyPlaygroundYeYe.playground:22:7: error: type 'DummyConsumer' does not conform to protocol 'Consumer'
class DummyConsumer: Consumer {
^
MyPlaygroundYeYe.playground:9:10: note: protocol requires function 'consume(_:item:)' with type '<P> (P, item: EmptyItem) -> ()' (aka '<τ_1_0> (τ_1_0, item: EmptyItem) -> ()')
func consume<P: Producer where P.T == T>(producer: P, item: T)
^
MyPlaygroundYeYe.playground:23:10: note: candidate has non-matching type '(DummyProducer, item: EmptyItem) -> ()' [with T = EmptyItem]
func consume(producer: DummyProducer, item: EmptyItem) {
^
有关该问题的解决方案(如果存在)的任何建议?
答案 0 :(得分:3)
您应该像这样定义您的课程DummyProducer
和DummyConsumer
:
class DummyProducer: Producer {
typealias T = EmptyItem
func registerConsumer<C: Consumer where C.T == T>(consumer: C) {
}
}
class DummyConsumer: Consumer {
typealias T = EmptyItem
func consume<P: Producer where P.T == T>(producer: P, item: T) {
}
}
由于您在协议定义中严格指定associatedType
T
为ItemType
,因此您无法在课程中仅使用EmptyItem
,因为{{1 }}不是唯一可以采用EmptyItem
协议的结构。