Question

我读过其他一些像我这样的帖子，但没有一个能解决我的问题，我有两个表，用户和购买，当用户注册时，我也想在购买表中添加相同的user_id。我尝试用这样的PHP代码：

$query = "CREATE TRIGGER `purchase_insert` AFTER INSERT ON `user` FOR EACH ROW BEGIN INSERT INTO purchase (user_id) VALUES (NEW.user_id)";

$result = mysqli_query($connection, $query);
if($result){echo "<br>TRIGGER Success!";} else {die("<br>Database query failed. " . mysqli_error($connection));}

这是我得到的错误：

Database query failed. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

如果问题重复，我很抱歉。

Answer 1

它应该回来打勾而不是单引号

CREATE TRIGGER `purchase_insert` AFTER INSERT ON `user` FOR EACH ROW BEGIN INSERT INTO purchase (user_id) VALUES (NEW.user_id)

<强>更新

试试这个

DELIMITER$$ 
CREATE TRIGGER `purchase_insert` 
    AFTER INSERT ON `user`
    FOR EACH ROW 
BEGIN
    INSERT INTO purchase (user_id) VALUES (NEW.user_id);
END$$
DELIMITER ;

MySQL使用php创建TRIGGER

1 个答案: