Question

我有3个表：结构，帐户范围和accountvalueUSD。从表结构中父和子ID的层次结构，我想创建一个这样的层次结构：

Level 1...Level 2...Level 3...Level 4....account...valueusd
111       112   113     114     100     1000
111     112     113     114     101     2000

表结构与表帐户范围链接，密钥为：financialitem

表acountrange链接表帐户值，密钥为：accountfrom，accountto为accountnumber

你能帮我怎么做吗？

    CREATE TABLE [dbo].[structure](
    [Financialitem] [nvarchar](3) NULL,
    [ID] [int] NULL,
    [ParentID] [int] NULL,
    [ChildID] [int] NULL,
    [NextID] [int] NULL,
    [Level] [int] NULL
) ON [PRIMARY]
INSERT INTO [dbo].[structure]
VALUES
(111,1,null,2,null,1),
(112,2,1,3,null,2),
(113,3,2,4,null,3),
(114,4,3,null,null,4),
(221,5,2,6,null,3),
(222,6,5,null,7,4),
(223,7,5,null,null,4)

    CREATE TABLE [dbo].[accountrange](
    [Financialitem] [nvarchar](3) NULL,
    [Accountfrom] [int] NULL,
    [Accountto] [int] NULL
) ON [PRIMARY]
INSERT INTO [dbo].[accountrange]
VALUES
(114,100,105),
(222,200,205),
(223,300,305)


    CREATE TABLE [dbo].[accountvalue](
    [accountnumber] [int] NULL,
    [valuesUSD] [int]  NULL,
) ON [PRIMARY]
INSERT INTO [dbo].[accountvalue]
VALUES
(100,1000),
(101,2000),
(301,1500),
(201,1400)

Answer 1

使用您提供的数据，此查询会显示您指定的输出。它被硬编码为4级，所以如果你需要更动态的东西，那么就需要进一步思考。

我还假设221分支没有出现的原因是因为它需要在父ID和子ID列上匹配。

select L1.Financialitem as [Level 1]
     , L2.Financialitem as [Level 2]
     , L3.Financialitem as [Level 3]
     , ar.Financialitem as [Level 4]
     , av.accountnumber, av.valuesUSD
from accountrange ar
inner join accountvalue av on av.accountnumber between ar.Accountfrom and ar.Accountto
inner join structure as L4 on L4.Financialitem = ar.Financialitem
inner join structure as L3 on L3.ID = L4.ParentID and L3.ChildID = L4.ID
inner join structure as L2 on L2.ID = L3.ParentID and L2.ChildID = L3.ID
inner join structure as L1 on L1.ID = L2.ParentID and L1.ChildID = L2.ID

如何创建此层次结构

1 个答案: