如何在mvc中将formcollection转换为模型

时间:2016-09-07 08:22:17

标签: asp.net-mvc asp.net-mvc-4 c#-4.0 formcollection

是否可以将formcollection转换为已知的“模型”?

[HttpPost]
    public ActionResult Settings(FormCollection fc)
    {
    var model=(Student)fc; // Error: Can't convert type 'FormCollection' to 'Student'
    }

注意:由于某些原因,我不能使用ViewModel。

这是我的代码VIEW:Settings.cshtml

@model MediaLibrarySetting
@{
ViewBag.Title = "Library Settings";
var extensions = (IQueryable<MediaLibrarySetting>)(ViewBag.Data);    
}
@helper EntriForm(MediaLibrarySetting cmodel)
{   

<form action='@Url.Action("Settings", "MediaLibrary")' id='MLS-@cmodel.MediaLibrarySettingID' method='post' style='min-width:170px' class="smart-form">
    @Html.HiddenFor(model => cmodel.MediaLibrarySettingID)
    <div class='input'>
        <label>
       New File Extension:@Html.TextBoxFor(model => cmodel.Extention, new { @class = "form-control style-0" })
        </label>
        <small>@Html.ValidationMessageFor(model => cmodel.Extention)</small>
    </div>
    <div>
        <label class='checkbox'>
            @Html.CheckBoxFor(model => cmodel.AllowUpload, new { @class = "style-0" })<i></i>&nbsp;
            <span>Allow Upload.</span></label>
    </div>
    <div class='form-actions'>
        <div class='row'>
            <div class='col col-md-12'>
                <button class='btn btn-primary btn-sm' type='submit'>SUBMIT</button>
            </div>
        </div>
    </div>
</form>
}
<tbody>
@foreach (var item in extensions)
 {
  if (item != null)
   {                                    
    <tr>
     <td>
      <label class="checkbox">
       <input type="checkbox"  value="@item.MediaLibrarySettingID"/><i></i>
        </label>
          </td>
           <td>
             <a href="javascript:void(0);" rel="popover" class="editable-click"
            data-placement="right"
            data-original-title="<i class='fa fa-fw fa-pencil'></i> File Extension"
            data-content="@EntriForm(item).ToString().Replace("\"", "'")" 
            data-html="true">@item.Extention</a></td>
                    </tr>
                    }
                }
                </tbody>

控制器:

[HttpPost]
public ActionResult Settings(FormCollection fc)//MediaLibrarySetting cmodel - Works fine for cmodel
{
        var model =(MediaLibrarySetting)(fc);// Error: Can't convert type 'FormCollection' to 'MediaLibrarySetting'
}

data-contentdata-属性是bootstrap popover。

3 个答案:

答案 0 :(得分:6)

MVC中的另一种方法是使用TryUpdateModel

实施例: TryUpdateModel或UpdateModel将从已发布的表单集合中读取并尝试将其映射到您的类型。我发现这比手动手动映射字段更优雅。

[HttpPost]
public ActionResult Settings()
{
    var model = new Student();

    UpdateModel<Student>(model);

    return View(model);
}

答案 1 :(得分:3)

好问题! 在制作通用基础控制器的过程中也是如此,模型独立。感谢很多人,最后一个是@GANI,已经完成了。

Type ViewModelType在子类控制器中设置为您想要的任何内容。

public ActionResult EatEverything(FormCollection form)
        {    
            var model = Activator.CreateInstance(ViewModelType);
            Type modelType = model.GetType();

        foreach (PropertyInfo propertyInfo in modelType.GetProperties())
        {
            var mykey = propertyInfo.Name;
            if (propertyInfo.CanRead && form.AllKeys.Contains(mykey))
            {
                try
                {
                    var value = form[mykey];
                    propertyInfo.SetValue(model, value);
                }
                catch 
                {
                    continue;
                }
            }
        }

现在您从未知表单收到的所有内容都在您的真实模型中,您可以通过此帖https://stackoverflow.com/a/22051586/7149454

继续进行验证

答案 2 :(得分:2)

你可以试试这种方式

   public ActionResult Settings(FormCollection formValues)
   {
     var student= new Student();
     student.Name = formValues["Name"];
     student.Surname = formValues["Surname"];
     student.CellNumber = formValues["CellNumber"];
    return RedirectToAction("Index");
   }