Question

我正在尝试启动Supervisor和GenServer：

defmodule SubscriptionManagerSupervisor do
  use Supervisor

  def start_link do
    Supervisor.start_link(__MODULE__, [], [{:name, __MODULE__}])
  end

  # supervisor callback
  def init([]) do
    interval = 1000
    children = worker(SubscriptionManagerServer, [interval])
    supervise(children, strategy: :one_for_one)
  end
end

我的GenServer：

defmodule SubscriptionManagerServer do
  use GenServer
  import Logger

  def start_link(interval) do
    GenServer.start_link(__MODULE__, [interval])
  end

  def init(interval) do
    state = :calendar.universal_time()
    Logger.info "SubscriptionManagerServer init(). State: #{state} interval: #{interval}"
    # This will send message to self on the interval. handle_info handles it.
    :timer.send_interval(interval)
    {:ok, state}
  end

  def handle_info(url, state) do
    new_state = :calendar.universal_time()
    Logger.info "SubscriptionManager handle_info(). new_state: #{new_state}"
    {:noreply, new_state}
  end
end

我尝试开始一切：

defmodule SubscriptionManagerApp do
  use Application
  import Logger

  def start(_type, _args) do
    Logger.info "Starting the SubscriptionManager."
    SubscriptionManagerSupervisor.start_link()
  end
end

但是，我收到以下错误：

** (Mix) Could not start application subscription_manager: SubscriptionManagerApp.start(:normal, []) returned an error: an exception was raised:
    ** c for {SubscriptionManagerServer, {SubscriptionManagerServer, :start_link, [1000]}, :permanent, 5000, :worker, [SubscriptionManagerServer]}
        (elixir) lib/enum.ex:1: Enumerable.impl_for!/1
        (elixir) lib/enum.ex:116: Enumerable.reduce/3
        (elixir) lib/enum.ex:1636: Enum.reduce/3
        (elixir) lib/enum.ex:1188: Enum.map/2
        (elixir) lib/supervisor/spec.ex:169: Supervisor.Spec.supervise/2
        (stdlib) supervisor.erl:294: :supervisor.init/1
        (stdlib) gen_server.erl:328: :gen_server.init_it/6
        (stdlib) proc_lib.erl:247: :proc_lib.init_p_do_apply/3

我试过改变一些论点并仔细查看文档，但我很难过。

Answer 1

代码中有几个问题：

<input type="button" id="submit" value="Submit" onclick="confirmSubmit()" class="smallGreenButton" />需要成为一个列表。
children的第二个参数应该只是GenServer.start_link，而不是interval。
在将其注入字符串插值之前，您需要[interval]状态，因为它是一个元组。
没有inspect()，只有:timer.send_interval/1和/2。

最后的修改：

/3

演示：

@@ -8,7 +8,7 @@ defmodule SubscriptionManagerSupervisor do
   # supervisor callback
   def init([]) do
     interval = 1000
-    children = worker(SubscriptionManagerServer, [interval])
+    children = [worker(SubscriptionManagerServer, [interval])]
     supervise(children, strategy: :one_for_one)
   end
 end
@@ -18,20 +18,20 @@ defmodule SubscriptionManagerServer do
   import Logger

   def start_link(interval) do
-    GenServer.start_link(__MODULE__, [interval])
+    GenServer.start_link(__MODULE__, interval)
   end

   def init(interval) do
     state = :calendar.universal_time()
-    Logger.info "SubscriptionManagerServer init(). State: #{state} interval: #{interval}"
+    Logger.info "SubscriptionManagerServer init(). State: #{inspect(state)} interval: #{interval}"
     # This will send message to self on the interval. handle_info handles it.
-    :timer.send_interval(interval)
+    :timer.send_interval(interval, :tick)
     {:ok, state}
   end

   def handle_info(url, state) do
     new_state = :calendar.universal_time()
-    Logger.info "SubscriptionManager handle_info(). new_state: #{new_state}"
+    Logger.info "SubscriptionManager handle_info(). new_state: #{inspect(new_state)}"
     {:noreply, new_state}
   end
 end

无法启动主管：（Protocol.UndefinedError）协议可枚举未实现

1 个答案: