Question

目前我的网站使用ajax脚本动态加载内容。这是脚本

/***********************************************
* Dynamic Ajax Content- (c) Dynamic Drive DHTML code library (www.dynamicdrive.com)
* Please keep this notice intact
* Visit Dynamic Drive at http://www.dynamicdrive.com/ for full source code
***********************************************/
var bustcachevar=1 //bust potential caching of external pages after initial request? (1=yes, 0=no)
var loadedobjects=""
var rootdomain="http://"+window.location.hostname
var bustcacheparameter=""

function ajaxpage(url, containerid){
var page_request = false
if (window.XMLHttpRequest) // if Mozilla, Safari etc
page_request = new XMLHttpRequest()
else if (window.ActiveXObject){ // if IE
try {
page_request = new ActiveXObject("Msxml2.XMLHTTP")
} 
catch (e){
try{
page_request = new ActiveXObject("Microsoft.XMLHTTP")
}
catch (e){}
}
}
else
return false
page_request.onreadystatechange=function(){
loadpage(page_request, containerid)
}
if (bustcachevar) //if bust caching of external page
bustcacheparameter=(url.indexOf("?")!=-1)? "&"+new Date().getTime() : "?"+new Date().getTime()
page_request.open('GET', url+bustcacheparameter, true)
page_request.send(null)
}

function loadpage(page_request, containerid){
if (page_request.readyState == 4 && (page_request.status==200 || window.location.href.indexOf("http")==-1))
document.getElementById(containerid).innerHTML=page_request.responseText
}

function loadobjs(){
if (!document.getElementById)
return
for (i=0; i<arguments.length; i++){
var file=arguments[i]
var fileref=""
if (loadedobjects.indexOf(file)==-1){ //Check to see if this object has not already been added to page before proceeding
if (file.indexOf(".js")!=-1){ //If object is a js file
fileref=document.createElement('script')
fileref.setAttribute("type","text/javascript");
fileref.setAttribute("src", file);
}
else if (file.indexOf(".css")!=-1){ //If object is a css file
fileref=document.createElement("link")
fileref.setAttribute("rel", "stylesheet");
fileref.setAttribute("type", "text/css");
fileref.setAttribute("href", file);
}
}
if (fileref!=""){
document.getElementsByTagName("head").item(0).appendChild(fileref)
loadedobjects+=file+" " //Remember this object as being already added to page
}
}
}

<p> Hello World! </p>

<a href="javascript:ajaxpage('example.html', 'content');">Form</a>
<div id="content"></div>

这部分工作很好我的内容是动态加载的问题出现当我尝试在加载的内容中提交一个PHP表单整个页面只是刷新我尝试使用JavaScript来阻止页面刷新，但仍然没有运气。我使用这个表单作为测试http://www.codingcage.com/2015/06/submit-php-form-without-page-refresh-jquery-ajax.html它在ajax内容之外正常运行但是当放在页面内时只需刷新！如果有人能给我一些如何解决这个问题的见解，我将不胜感激

Answer 1

我认为这是因为您的表单是动态生成的，因此事件处理程序不会捕获您的提交事件。它发生在我身上很多次，我做的是这样的事情。我有我的选择器静态内容。 return

Ajax导航和表单提交

1 个答案: