让一切都清楚我有这两个表
table 1
-------------------------------
id | name | email | created_at
x | x | x | 2016:09:01
x | x | x | 2016:09:01
x | x | x | 2016:09:01
x | x | x | 2016:09:02
x | x | x | 2016:09:04
x | x | x | 2016:09:04
-------------------------------
table 2
-------------------------------
id | name | email | created_at
x | x | x | 2016:09:03
x | x | x | 2016:09:03
x | x | x | 2016:09:05
-------------------------------
用户必须选择两个日期开始和结束 让我说他\她选择了开始= 2016:09:01和结束= 2016:09:07 所以我需要像这样显示结果
result
-------------------------------
num_of_recs_t1 | num_of_recs_t2 | day
3 | 0 | 2016:09:01
1 | 0 | 2016:09:02
0 | 2 | 2016:09:03
2 | 0 | 2016:09:04
0 | 1 | 2016:09:05
0 | 0 | 2016:09:06
0 | 0 | 2016:09:07
我正在使用带有学说的Symfony 3并且说实话我甚至不认为我可以使用正常的mysql命令
提前致谢
答案 0 :(得分:0)
在控制器中试试
$db = $this->getDoctrine()->getConnection();
$data = $db->fetchAll("
select
t1.num_of_recs as num_of_recs_t1,
t2.num_of_recs as num_of_recs_t2,
t1.created_at
from
(
select created_at, count(*) as num_of_recs
from table_1
group by created_at
) t1
join (
select created_at, count(*) as num_of_recs
from table_2
group by created_at
) t2
on t1.created_at = t2.created_at
order by
t1.created_at");
dump($data);