假设我们有两个带有以下密钥对值的字典：
我想创建一个字典，如下所示： 字典3：[{abc，123} {cde，234} {efg，345}]
removeHobby(index: number){
(<FormArray>this.myForm.find('hobbies')).removeAt(index);
}
我尝试了上述内容，但是我在
处获得了超出范围异常的索引 fieldValues = new List<List<string>>();
docFieldKey = new List<List<string>>();
docFieldValueDict = new Dictionary<string, List<string>>();
docKeyDict = new Dictionary<string, List<string>>();
iterateDocKeyDict = new List<string>();
iterateDocFldValueDict = new List<string>();
//To read row wise and store key and all values
for (limit = 0; limit < docNames.Count; limit++)
{
for (row = 0; row < excelData.Count; row++)
{
if (excelData[row] == docNames[limit])
{
for (colLimit = row + 1; colLimit < fieldNames.Count; colLimit++)
{
flag = true;
fieldValues.Add(new List<string>());
fieldValues[limit].Add(excelData[colLimit]);
}
if (flag == true)
{
docFieldValueDict.Add(docNames[limit], fieldValues[limit]);
}
}
}
}
//To add concatenated key for each docName
for (limit = 0; limit < docNames.Count; limit++)
{
for (colLimit = 0; colLimit < concatKey.Count; colLimit++)
{
if (concatKey[colLimit].Contains(docNames[limit]))
{
for (col = colLimit; col < fieldNames.Count - 1; col++)
{
flag = true;
docFieldKey.Add(new List<string>());
docFieldKey[limit].Add(concatKey[col]);
}
if (flag == true)
{
docKeyDict.Add(docNames[limit], docFieldKey[limit]);
}
}
}
}
//to merge the key and the value from both dictionaries
for (limit = 0; limit <docKeyDict.Count; limit++)
{
var docKeyDictCompare = docKeyDict.ElementAt(limit);
var docFldValueDictCompare = docFieldValueDict.ElementAt(limit);
iterateDocKeyDict = docKeyDictCompare.Value;
iterateDocFldValueDict = docFldValueDictCompare.Value;
if (docKeyDictCompare.Key == docFldValueDictCompare.Key)
{
for (col = 0; col < fieldNames.Count - 1; col++)
{
if ((iterateDocKeyDict.ElementAt(col)!=string.Empty) && (iterateDocFldValueDict.ElementAt(col)!=string.Empty))
{
flag = true;
}
}
if (flag == true)
{
keyValuePairDict.Add(iterateDocKeyDict.ElementAt(col), iterateDocFldValueDict.ElementAt(col));
}
}
}
Error msg displayed in Console
答案 0 :(得分：8)
只要查看您的示例词典，我就会建议：
var dic1 = /* [ {1,abc} {2,cde} {3,efg} ] */;
var dic2 = /* [ {1,123} {2,234} {3,345} ] */;
var dic3 = dic1.ToDictionary(x => x.Value, x => dic2[x.Key]);
但是看一下相当长的代码示例，我不确定它是否足够。
答案 1 :(得分：1)
试试这样：
var dictionaryC = dictionaryA.ToDictionary(dicA => dicA.Value, dicA => dictionaryB[dicA.Key]);