Question

假设我们有两个带有以下密钥对值的字典：

字典1：[{1，abc} {2，cde} {3，efg}]
字典2：[{1,123} {2,234} {3,345}]
我想创建一个字典，如下所示：字典3：[{abc，123} {cde，234} {efg，345}]
```
removeHobby(index: number){
(<FormArray>this.myForm.find('hobbies')).removeAt(index);
}
```

我尝试了上述内容，但是我在

处获得了超出范围异常的索引

fieldValues = new List<List<string>>(); docFieldKey = new List<List<string>>(); docFieldValueDict = new Dictionary<string, List<string>>(); docKeyDict = new Dictionary<string, List<string>>(); iterateDocKeyDict = new List<string>(); iterateDocFldValueDict = new List<string>(); //To read row wise and store key and all values for (limit = 0; limit < docNames.Count; limit++) { for (row = 0; row < excelData.Count; row++) { if (excelData[row] == docNames[limit]) { for (colLimit = row + 1; colLimit < fieldNames.Count; colLimit++) { flag = true; fieldValues.Add(new List<string>()); fieldValues[limit].Add(excelData[colLimit]); } if (flag == true) { docFieldValueDict.Add(docNames[limit], fieldValues[limit]); } } } } //To add concatenated key for each docName for (limit = 0; limit < docNames.Count; limit++) { for (colLimit = 0; colLimit < concatKey.Count; colLimit++) { if (concatKey[colLimit].Contains(docNames[limit])) { for (col = colLimit; col < fieldNames.Count - 1; col++) { flag = true; docFieldKey.Add(new List<string>()); docFieldKey[limit].Add(concatKey[col]); } if (flag == true) { docKeyDict.Add(docNames[limit], docFieldKey[limit]); } } } } //to merge the key and the value from both dictionaries for (limit = 0; limit <docKeyDict.Count; limit++) { var docKeyDictCompare = docKeyDict.ElementAt(limit); var docFldValueDictCompare = docFieldValueDict.ElementAt(limit); iterateDocKeyDict = docKeyDictCompare.Value; iterateDocFldValueDict = docFldValueDictCompare.Value; if (docKeyDictCompare.Key == docFldValueDictCompare.Key) { for (col = 0; col < fieldNames.Count - 1; col++) { if ((iterateDocKeyDict.ElementAt(col)!=string.Empty) && (iterateDocFldValueDict.ElementAt(col)!=string.Empty)) { flag = true; } } if (flag == true) { keyValuePairDict.Add(iterateDocKeyDict.ElementAt(col), iterateDocFldValueDict.ElementAt(col)); } } } Error msg displayed in Console

Answer 1

只要查看您的示例词典，我就会建议：

var dic1 = /* [ {1,abc} {2,cde} {3,efg} ] */;
var dic2 = /* [ {1,123} {2,234} {3,345} ] */;
var dic3 = dic1.ToDictionary(x => x.Value, x => dic2[x.Key]);

但是看一下相当长的代码示例，我不确定它是否足够。

Answer 2

试试这样：

var dictionaryC = dictionaryA.ToDictionary(dicA => dicA.Value, dicA => dictionaryB[dicA.Key]);

如何使用具有相同键的两个不同字典的值来构建新字典

2 个答案: