Question

我试过这段代码，但它对我不起作用。我只想将数组值添加到数据库中。它给我这样的错误

注意：未定义的偏移量：2

这是我的代码：

$timeadd = date("m-d-Y H:i:s", strtotime('+6 hours'));      

$extinvoice=mysqli_query($link,"Select * from invoice WHERE BRANCH_CODE_MX='".$display_branchcode."' and INVOICE_NO_MX='".$invoicecode."' and INVOICE_ITEM_UNIT_MX='EXTENDEDWARRANTY'");
while($extrow=mysqli_fetch_array($extinvoice))
{
    $ewtitemcode=$extrow["INVOICE_ITEM_CODE_MX"];
    $imeiserialunit=$extrow["EWT_IMEI_MX"];
    $customercode=$extrow["INVOICE_CUS_CODE_MX"];
    $ewtarray[] = "('$invoicecode','$ewtitemcode', '$imeiserialunit','$customercode','$display_branchcode','$timeadd')";

}
$arrayitem=count($ewtarray); 

for($item = 0; $item <= $arrayitem; $item++)
{
    $sql = mysqli_query($link,"INSERT INTO extended_warranty
        (INVOICE_NO_MX,FORM_EW_MX,EW_SERIAL_MX,CUSTOMER_CODE,BRANCH_CODE_MX,DATE_ADDED)
        VALUES
        ($ewtarray[$item])");

}

Answer 1

数据库需要格式为

的数据时间

2016-10-02 10:00:00

所以改变这个

$timeadd = date("m-d-Y H:i:s", strtotime('+6 hours'));

到

$timeadd = date("Y-m-d H:i:s", strtotime('+6 hours'));

Answer 2

除了其他用户，我删除了双括号。现在发生了什么？

$timeadd = date("Y-m-d H:i:s", strtotime('+6 hours'));     

$extinvoice=mysqli_query($link,"Select * from invoice WHERE BRANCH_CODE_MX='".$display_branchcode."' and INVOICE_NO_MX='".$invoicecode."' and INVOICE_ITEM_UNIT_MX='EXTENDEDWARRANTY'");
while ($extrow=mysqli_fetch_array($extinvoice)) {
    $ewtitemcode=$extrow["INVOICE_ITEM_CODE_MX"];
    $imeiserialunit=$extrow["EWT_IMEI_MX"];
    $customercode=$extrow["INVOICE_CUS_CODE_MX"];
    $ewtarray[] = "('$invoicecode','$ewtitemcode', '$imeiserialunit','$customercode','$display_branchcode','$timeadd')";
}

for ($item = 0; $item < count($ewtarray); $item++) {
    $sql = mysqli_query($link,"INSERT INTO extended_warranty
        (INVOICE_NO_MX,FORM_EW_MX,EW_SERIAL_MX,CUSTOMER_CODE,BRANCH_CODE_MX,DATE_ADDED)
        VALUES
        $ewtarray[$item]");
}

在数据库中添加值（Array）

2 个答案: