Question

表名：Citizen

Firstname       Lastname    Telephone1         Many other columns......
John             Smith      03907625212    
Andrew           Evans      0807452132    
Bill             Towny      05907122139  
Dame             Beaut      07894650569

理想情况应如下所示：

Firstname       Lastname      Telephone1         Many other columns......
John             Smith       01907000001   
Andrew           Evans       01907000002  
Bill             Towny       01907000003 
Dame             Beaut       01907000004

之前，有人能够使用select语句提供脚本。 Script for incrementally creating records

select [First Name], 
       [Last Name], 
       [All LP Surname], 
       [All Liable Partys PIN], 
       '01907' + RIGHT('00000' + CAST(ROW_NUMBER() OVER (ORDER BY [Last Name]) AS VARCHAR), 6) AS 'Telephone1', 
       [Telephone2], 
       [Mobilephone], 
       [EmailAddress] 
FROM citizen

但是我想要实现更改，因为我只能使用上面的选择脚本来查看它们。

Answer 1

这不需要JOIN。您可以使用添加的新列的值直接从CTE更新。我假设您希望将Telephone1列设置为等于查询的计算Telephone1列。这是以下代码：

;With ToUpdate As
(
    Select *,
           '01907' + 
               Right('00000' + 
                   Cast(Row_Number() Over (Order By [Last Name]) As Varchar)
                , 6) 
           As NewTelephone1
    From   Citizen
)
Update  ToUpdate
Set     Telephone1 = NewTelephone1

这会将您的citizen表的Telephone1列更新为计算出的NewTelephone1的值。

Answer 2

UPDATE c
SET c.[Telephone] = '0' + CAST(1907000000 + t.RowNumber AS VARCHAR)
FROM Citizen c
INNER JOIN
(
    SELECT [First Name], 
           [Last Name], 
           ROW_NUMBER() OVER (ORDER BY [Last Name], [First Name]) AS RowNumber
    FROM Citizen
) t
    ON c.[First Name] = t.[First Name] AND
       c.[Last Name]  = t.[Last Name]

Answer 3

您需要使用CTE作为窗口函数。像这样：

WITH cte AS
    (
    SELECT
        [All Liable Partys PIN], 
        '01907' + RIGHT('00000' + CAST(ROW_NUMBER() OVER (ORDER BY [LastName]) AS VARCHAR), 6) AS 'NewTelephone1'
    FROM
        [citizen]
    )

UPDATE
    c
SET
    c.[Telephone1] = cte.[NewTelephone1]
FROM
    [citizen] c
    JOIN cte
        ON c.[All Liable Partys PIN] = cte.[All Liable Partys PIN]

我在这里假设我们可以使用PIN字段加入。

用于更新列的脚本

3 个答案: