Question

是否有更合适的方法来使一个子字符串比这个更简单？：

string[a..b] = string[a..b].downcase

也许是这样的：

string[a..b].downcase!

例如：

string = "RubyChangedMyMind"

string[1..string.length] = string[1..string.length].downcase 
# this is working but i want to know if there is more short way to do this
# (indeces may be different)
# something like string[a..b].downcase!

Answer 1

你可以制作proc：

~/.gitconfig

并随时调用它：

[alias]
 mergeRepo = "!mergeRepo() { \
  [ $# -ne 3 ] && echo \"Three parameters required, <remote URI> <new branch> <new dir>\" && exit 1; \
  git remote add newRepo $1; \
  git fetch newRepo; \
  git branch \"$2\" newRepo/master; \
  git checkout \"$2\"; \
  mkdir -vp \"${GIT_PREFIX}$3\"; \
  git ls-tree -z --name-only HEAD | xargs -0 -I {} git mv {} \"${GIT_PREFIX}$3\"/; \
  git commit -m \"Moved files to '${GIT_PREFIX}$3'\"; \
  git checkout master; git merge --allow-unrelated-histories --no-edit -s recursive -X no-renames \"$2\"; \
  git branch -D \"$2\"; git remote remove newRepo; \
}; \
mergeRepo"

例如：

my_downcase = Proc.new { |str,n,m| str.chars.each_with_index.map{ |c,index| (n..m).include?(index) ? c.downcase : c }.join}

Ruby substring downcase

1 个答案: