拦截/处理React-router中的浏览器后退按钮?

时间:2016-09-06 06:44:06

标签: javascript reactjs react-router material-ui

我正在使用Material-ui的标签,这些标签受到控制,我将它们用于(React-router)链接,如下所示:

    <Tab value={0} label="dashboard" containerElement={<Link to="/dashboard/home"/>}/>
    <Tab value={1} label="users" containerElement={<Link to="/dashboard/users"/>} />
  <Tab value={2} label="data" containerElement={<Link to="/dashboard/data"/>} />

如果我当前正在访问仪表板/数据,请点击浏览器的后退按钮 我(例如)转到仪表板/用户,但突出显示的Tab仍然停留在仪表板/数据上(值= 2)

我可以通过设置状态进行更改,但是当按下浏览器的后退按钮时,我不知道如何处理该事件?

我发现了这个:

window.onpopstate = this.onBackButtonEvent;

但每次状态更改时都会调用此命令(不仅仅是在后退按钮事件中)

15 个答案:

答案 0 :(得分:19)

这是一个有点老问题,你可能已经得到了答案,但对于像我这样需要这个问题的人,我会留下这个答案。

使用react-router使这项工作变得简单:

import { browserHistory } from 'react-router';

componentDidMount() {
    super.componentDidMount();

    this.onScrollNearBottom(this.scrollToLoad);

    this.backListener = browserHistory.listen(location => {
      if (location.action === "POP") {
        // Do your stuff
      }
    });
  }

componentWillUnmount() {
    super.componentWillUnmount();
    // Unbind listener
    this.backListener();
}

答案 1 :(得分:14)

使用钩子可以检测到后退和前进按钮

import { useHistory } from 'react-router-dom'


const [ locationKeys, setLocationKeys ] = useState([])
const history = useHistory()

useEffect(() => {
  return history.listen(location => {
    if (history.action === 'PUSH') {
      setLocationKeys([ location.key ])
    }

    if (history.action === 'POP') {
      if (locationKeys[1] === location.key) {
        setLocationKeys(([ _, ...keys ]) => keys)

        // Handle forward event

      } else {
        setLocationKeys((keys) => [ location.key, ...keys ])

        // Handle back event

      }
    }
  })
}, [ locationKeys, ])

答案 2 :(得分:9)

这是我最终如何做到的:

Activity

感谢大家帮助lol

答案 3 :(得分:6)

React Router API的3.x版本a set of utilities可用于公开&#34; Back&#34;事件之前的按钮事件注册浏览器的历史记录。您必须首先将组件包装在withRouter() higher-order component中。然后,您可以使用setRouteLeaveHook()函数,该函数接受具有有效route属性和回调函数的任何path对象。

import {Component} from 'react';
import {withRouter} from 'react-router';

class Foo extends Component {
  componentDidMount() {
    this.props.router.setRouteLeaveHook(this.props.route, this.routerWillLeave);
  }

  routerWillLeave(nextState) { // return false to block navigation, true to allow
    if (nextState.action === 'POP') {
      // handle "Back" button clicks here
    }
  }
}

export default withRouter(Foo);

答案 4 :(得分:3)

用于在反应功能组件中向按下浏览器时发出警告。请执行以下步骤

  1. 声明isBackButtonClicked并将其初始化为false并使用setBackbuttonPress函数维护状态。
const [isBackButtonClicked, setBackbuttonPress] = useState(false);
  1. 在componentdidmount中,添加以下代码行
window.history.pushState(null, null, window.location.pathname);
window.addEventListener('popstate', onBackButtonEvent);
  1. 定义onBackButtonEvent函数并根据需要编写逻辑。

      const onBackButtonEvent = (e) => {
      e.preventDefault();
      if (!isBackButtonClicked) {
    
      if (window.confirm("Do you want to go to Test Listing")) {
        setBackbuttonPress(true)
        props.history.go(listingpage)
      } else {
        window.history.pushState(null, null, window.location.pathname);
        setBackbuttonPress(false)
      }
    }
    

    }

  2. 在组件中将取消订阅onBackButtonEvent函数

最终代码如下所示

import React,{useEffect,useState} from 'react'

function HandleBrowserBackButton() {
  const [isBackButtonClicked, setBackbuttonPress] = useState(false)

  useEffect(() => {

    window.history.pushState(null, null, window.location.pathname);
    window.addEventListener('popstate', onBackButtonEvent);

    //logic for showing popup warning on page refresh
    window.onbeforeunload = function () {

      return "Data will be lost if you leave the page, are you sure?";
    };
    return () => {
      window.removeEventListener('popstate', onBackButtonEvent);
    }

    // eslint-disable-next-line react-hooks/exhaustive-deps
  }, []);
  const onBackButtonEvent = (e) => {
    e.preventDefault();
    if (!isBackButtonClicked) {

      if (window.confirm("Do you want to go to Test Listing")) {
        setBackbuttonPress(true)
        props.history.go(listingpage)
      } else {
        window.history.pushState(null, null, window.location.pathname);
        setBackbuttonPress(false)
      }
    }
  }

  return (
    <div>

    </div>
  )
}

export default HandleBrowserBackButton

答案 5 :(得分:1)

我与router hoc一起使用是为了获取历史记录道具,并只编写一个componentDidMount()方法:

componentDidMount() {
    if (this.props.history.action === "POP") {
        // custom back button implementation
    }
}

答案 6 :(得分:1)

挂钩样本

    const { history } = useRouter();

useEffect(() => {
    return () => {
        if (history.action === "POP") // && history.location.pathname === "any specific path") {
            history.replace(history.location.pathname, /* the new state */);
        }
    };
}, [history])

我不使用history.listen,因为它不会影响状态

const disposeListener = history.listen(navData => {
        if (navData.pathname === "/props") {
            navData.state = /* the new state */;
        }
    });

答案 7 :(得分:1)

这取决于您在React中使用的路由器的类型。

如上所述,如果您从react-router使用BrowserRouter(尽管在react-router v4中不可用),则可以使用操作“ POP”来拦截浏览器后退按钮。

但是,如果您使用HashRouter推送路由,则上述解决方案将不起作用。原因是当您单击浏览器的后退按钮或从组件中推入路由时,哈希路由器始终以“ POP”操作触发。您无法通过window.popstate或history.listen来区分这两个动作。

答案 8 :(得分:1)

该问题的大多数答案要么使用过时的React Router版本,要么依赖不太现代的Class组件,要么令人困惑;而且都不使用Typescript,这是一种常见的组合。这是使用Router v5,功能组件和Typescript的答案:

// use destructuring to access the history property of the ReactComponentProps type
function MyComponent( { history }: ReactComponentProps) {

    // use useEffect to access lifecycle methods, as componentDidMount etc. are not available on function components.
    useEffect(() => {

        return () => {
            if (history.action === "POP") {
                // Code here will run when back button fires. Note that it's after the `return` for useEffect's callback; code before the return will fire after the page mounts, code after when it is about to unmount.
                }
           }
    })
}

here中提供了带有说明的完整示例。

答案 9 :(得分:1)

如果你使用的是 React Router V5,你可以试试 Prompt

<块引用>

用于在离开页面之前提示用户。当您的应用程序进入应阻止用户导航离开的状态时(例如表单填写了一半),呈现

<Prompt
   message={(location, action) => {
   if (action === 'POP') {
      console.log("Backing up...")
      // Add your back logic here
   }

   return true;
   }}
/>

答案 10 :(得分:1)

只需放入 componentDidMount()

componentDidMount() {
    window.onbeforeunload =this.beforeUnloadListener;
} 
beforeUnloadListener = (event) => {
    event.preventDefault();
    return event.returnValue = "Are you sure you want to exit?";
};

答案 11 :(得分:0)

即将发布的6.0版引入了useBlocker钩子-可用于拦截所有导航尝试。

import { Action } from 'history';
import { useBlocker } from 'react-router';

// when blocker should be active
const unsavedChanges = true;

useBlocker((transition) => {
    const {
        location, // The new location
        action, // The action that triggered the change
    } = transition;

    // intercept back and forward actions:
    if (action === Action.Pop) {
        alert('intercepted!')
    }

}, unsavedChanges);

答案 12 :(得分:0)

使用挂钩。我已经将@Nicolas Keller的代码转换为打字稿

  const [locationKeys, setLocationKeys] = useState<(string | undefined)[]>([]);
  const history = useHistory();

  useEffect(() => {
    return history.listen((location) => {
      if (history.action === 'PUSH') {
        if (location.key) setLocationKeys([location.key]);
      }

      if (history.action === 'POP') {
        if (locationKeys[1] === location.key) {
          setLocationKeys(([_, ...keys]) => keys);

          // Handle forward event
          console.log('forward button');
        } else {
          setLocationKeys((keys) => [location.key, ...keys]);

          // Handle back event
          console.log('back button');
          removeTask();
        }
      }
    });
  }, [locationKeys]);

答案 13 :(得分:0)

您现在可以使用 react-router-dom 中的 useHistory 钩子

import { useHistory } from "react-router-dom";

const history = useHistory();

...

<div onClick={ ()=>history.goBack() }>Back </div>

这将通过点击导航到上一页

答案 14 :(得分:-3)

您可以使用“ withrouter” HOC并使用this.props.history.goBack

<Button onClick={this.props.history.goBack}>
    BACK
</Button>