Question

我有来自sum函数的查询数据：

ROUND(((nominal)*12) * ROUND((SUM((a.NCI)/3*(60/100))+SUM((b.NSI)/3*(40/100)))/3,2)/100,2) AS nominal_persentasi,
ROUND((((nominal)*12) * ROUND((SUM((a.NCI)/3*(60/100))+SUM((b.NSI)/3*(40/100)))/3,2))*(1.1/100)/100,2) AS tambah_persentasi,
ROUND((((nominal)*12) *  ROUND((SUM((a.NCI)/3*(60/100))+SUM((b.NSI)/3*(40/100)))/3,2))+((((nominal)*12) *  ROUND((SUM((a.NCI)/3*(60/100))+SUM((b.NSI)/3*(40/100)))/3,2))*(1.1/100))/100,2) AS total_penyesuaian

结果是：

nominal_persentasi | tambah_persentasi | total_penyesuaian
12.000               3.000               1.203.000

产生的结果应该是15,000，为什么会发生？

我尝试对变量nominal_persentasi + tambah_persentasi求和，但结果为0。

Answer 1

您在总数中错过了100的分组。因此，您不必添加12,000和3,000来获取15,000，而是实际添加12,000,000和3,000以获取12,003,000。

SELECT ROUND(( (nominal)*12) *  ROUND((SUM((a.NCI)/3*(60/100))+SUM((b.NSI)/3*(40/100)))/3,2)/100,2) AS nominal_persentasi,
       ROUND((((nominal)*12) *  ROUND((SUM((a.NCI)/3*(60/100))+SUM((b.NSI)/3*(40/100)))/3,2))*(1.1/100)/100,2) AS tambah_persentasi,
       ROUND((((nominal)*12) *  ROUND((SUM((a.NCI)/3*(60/100))+SUM((b.NSI)/3*(40/100)))/3,2)/100) + ((((nominal)*12) *  ROUND((SUM((a.NCI)/3*(60/100))+SUM((b.NSI)/3*(40/100)))/3,2))*(1.1/100))/100, 2) AS total_penyesuaian
FROM yourTable                      -- your query was missing this division by 100           ^^^

如何用多个sum修复查询mysql

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