从patient_detail_search.php成功获取ajax后,如何在patient_info.php中的div元素上显示值?
在patient_detail_search.php中搜索js
$('.search').on('click', function(){
var search_by = $('.search_lists').val();
var search_text = $('.search_text').val();
$.ajax({
url: 'patient_search.php',
type: 'POST',
data: {patient_search_by: search_by, patient_search_text: search_text},
success:function(response){
//... Get response value to display on patient_info.php
}
});
});
从patient_detail_search.php获取响应值,以显示在patient_info.php中的div元素
<div class="patient_detail_box">
<!-- response value here -->
</div>
答案 0 :(得分:0)
您可以使用.html()
函数(jQuery doc here)或.text()
函数(jQuery doc here)将内容插入元素中。在您的情况下,您可以尝试:
$('.search').on('click', function(){
var search_by = $('.search_lists').val();
var search_text = $('.search_text').val();
$.ajax({
url: 'patient_search.php',
type: 'POST',
data: {patient_search_by: search_by, patient_search_text: search_text},
success:function(response){
//... Send response value to class="patient_detail_box" on patient_info.php
$('.patient_detail_box').html("Response from server: " + response);
}
});
});