Question

在我的例子中，我有两个循环。一个嵌套在另一个中。有没有办法可以从外部索引开始内循环。这是伪代码。

arrayOfWords = ["one","two","five"]
arrayOfWords2 = ["one","two","three","four","five"]
tottalWordlist = []
for index, jString in enumerate(arrayOfWords):
    gWord = arrayOfWords[index]
    indexClone = index
    arrayOfWords2Count = range(len(arrayOfWords2)-1)
    for indexClone in arrayOfWords2Count:
        if gWord == arrayOfWords2[indexClone]:
            tottalWordlist.append(gWord)
            break

Answer 1

你几乎就在那里。您只需要将起始索引添加到range对象。

arrayOfWords2Count = range(indexClone, len(arrayOfWords2))
for i in arrayOfWords2Count:
    if gWord == arrayOfWords2[i]:

此外，您不需要从端点中减去一个，因为该端是独占的。

Answer 2

在我的理解中，您正在寻找内部列表中的外部列表元素是否以外部元素的索引开头。

arrayOfWords = ["one","two","five"]
arrayOfWords2 = ["one","two","three","four","five"]


print [ item for i,item in enumerate(arrayOfWords) if item in arrayOfWords2[i:] ]

['one', 'two', 'five']

从外部位置开始内循环

2 个答案: