Question

我陷入了下面的问题。我用while循环完成了这个并且它工作正常但是不能省略每个循环中附加字符串的序列号。

我有文件内容

1 SELECT abc from a ;

   2 .IF activi <> 1
   3 THEN 
   4 QUIT;
   5 .IF ERROR <> 0 THEN QUIT ERROR;
   6 SELECT 
   7 a,
   8 b,
   9 c
   10 FROM xyz;
   11 .IF ERROR <> 0
   12 THEN 
   13 QUIT ERROR;

我想在同一个文件中编辑使用以下输出

1 SELECT abc from a;    
   2 .IF activi <> 1 THEN QUIT ;
   5 .IF ERROR <> 0 THEN QUIT ERROR;   
   6 SELECT 
   7 a,
   8 b,
   9 c
   10 FROM xyz;    
   11 .IF ERROR <> 0 THEN QUIT ERROR;

Answer 1

使用sed：

$ sed '/\.IF/{:a;/; *$/!{N;s/ *\n *[0-9]*//;ta}}' file

输出：

1 SELECT abc from a ;

   2 .IF activi <> 1 THEN QUIT;
   5 .IF ERROR <> 0 THEN QUIT ERROR;
   6 SELECT 
   7 a,
   8 b,
   9 c
   10 FROM xyz;
   11 .IF ERROR <> 0 THEN QUIT ERROR;

<强>解释

sed '
/\.IF/ {                   # for lines containing ".IF"
    :a;                    # define a "a" label for upcoming loop
    /; *$/! {              # if line does not contain ";"
        N;                 # add next line to pattern space
        s/ *\n *[0-9]*//;  # remove newline and leading digits
        ta;                # loops to label "a" if ";" is not found
    }
}' file

合并从IF开始的所有行，并在shell脚本中以分号结束

1 个答案: