如何获取,修改和发布json对象?

时间:2016-09-05 13:16:05

标签: java json http-post http-get

3天前在我的旧话题中提到 - Last Topic

我得到了一个json响应并将其更改为字符串。 Json Response表示用户对象。在User-Object中,我想搜索特定项目并将其删除。之后,我想通过HttpPost再次发布它。

    private static String getContent(HttpResponse response) {
HttpEntity entity = response.getEntity();
if (entity == null) return null;
BufferedReader reader;
try {
    reader = new BufferedReader(new InputStreamReader(entity.getContent()));
    String line = reader.readLine();
    reader.close();
    return line;
} catch (IllegalStateException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
}
return null;

}

String StringResponse = getContent(JsonResponse);
JSONObject jsonObject = new JSONObject(StringResponse);
JSONArray ProjectsArray= jsonObject.getJSONArray("projects");

通过在JsonArray中保存属性来搜索特定项目。

ArrayList<Integer> indexesToRemove = new ArrayList<Integer>();
for (int i = 0; i < projectsArray.length; i++) {
JSONObject current = projectsArray.get(i);
if (current.get("projectKey") == "**ProjectName**") {
indexesToRemove.add(i);
}
} 

删除项目......

for (int i = indexesToRemove.size()-1; i>=0; i--) 
{ 
projectsArray.remove(indexesToRemove.get(i));
}

这很有效,我的搜索项目也被删除了。但问题是,我想通过HttpPost再次发布修改后的UserObject / String。我删除的项目只是在我的JsonArray“projectsArray”中,而不是从一开始就在我的字符串中。我不能发布“projectsArray”....

        HttpPost UserChange = new HttpPost (TestUserURL+user);  //TODO: 
        UserChange.setHeader("Accept", "application/json");
        UserChange.setHeader("Content-type", "application/json");

        params = new StringEntity("ModifiedJsonString", HTTP.UTF_8);   // How do i get the complete Json string?
        UserChange.setEntity(params);

        HttpResponse UserChangeResponse = httpclient.execute(UserChange);

        HttpEntity entity2 = UserChangeResponse.getEntity();
            if (entity2 != null) {
                entity2.consumeContent();                       
            }

我需要“ModifiedJsonString”,它从头开始包含完整的json文件。

params = new StringEntity(ModifiedJsonString, HTTP.UTF_8);

最好的问候

1 个答案:

答案 0 :(得分:0)

以下代码会删除所选项目之一。

String jsonString = "{    \"account\": \"Kpatrick\",    \"firstname\": \"Patrick\",    \"instances\": [        {            \"id\": \"packerer-pool\",            \"key\": \"packerer-pool123\",            \"userAccount\": \"kpatrick\",            \"firstname\": \"Patrick\",            \"lastname\": \"Schmidt\"        }    ],    \"projects\": [        {            \"id\": \"packerer-projectPool\",            \"projectKey\": \"projectPool-Pool\",            \"cqprojectName\": \"xxxxx\"        },        {            \"id\": \"packerer-secondproject\",            \"projectKey\": \"projectPool-Pool2\",            \"cqprojectName\": \"xxxx\"        },        {            \"id\": \"packerer-thirdproject\",            \"projectKey\": \"projectPool-Pool3\",            \"cqprojectName\": \"xxxx\"        }    ],    \"clients\": [],    \"dbid\": 76864576,    \"version\": 1,    \"id\": \"dbpack21\"}";
JSONParser parser = new JSONParser();
JSONObject jsonObject = (JSONObject) parser.parse(jsonString);

ArrayList<String> listOfNodes = new ArrayList<String>();
JSONArray projectArray = (JSONArray) jsonObject.get("projects");
int len = projectArray.size();
if (projectArray != null) {
    for (int i = 0; i < len; i++) {
        String projectId = ((JSONObject) projectArray.get(i)).get("projectKey").toString();
        if (!projectId.equals("projectPool-Pool2")) {
            listOfNodes.add(projectArray.get(i).toString());

        }

    }
}
// Remove the element from arraylist
// Recreate JSON Array
JSONArray jsArray = new JSONArray();
jsArray.addAll(listOfNodes);
jsonObject.remove(projectArray);
jsonObject.put("projects", listOfNodes);

System.out.println(jsonObject.toString());

例如,打印以下JSON字符串,删除其中一个项目。Linted JSON 完成后,您可以使用它来创建StringEntity,然后在HTTPPost调用中使用它。希望它有所帮助