解析具有不确定数据的json

Question

如何解析具有Assets对象的json未知？

作为

{   
    "ClassName": "Excel",
    "Teacher": "Esther",
    "Student": 50,
    "Aircond": 0,
    "Assets": {
        "Chair": 50,
        "Table": 50,
        "Fan": 2,
        and might be more here and is unknown to me
    }
}

Answer 1

如果您确定Assets只是一堆具有不同类型值的键，那么您可以使用IDictionary<string, object>来存储Assets：

public class MyClass
{
    public string ClassName { get; set; }
    public string Teacher { get; set; }
    public int Student { get; set; }
    public int Aircond { get; set; }
    public IDictionary<string, object> Assets { get; set; }
}

var myClass = JsonConvert.DeserializeObject<MyClass>(json);

Answer 2

您可以将dynamic用作Assets类型：

public class RootObject
{
    public string ClassName { get; set; }
    public string Teacher { get; set; }
    public int Student { get; set; }
    public int Aircond { get; set; }
    public dynamic Assets { get; set; }
}

然后

RootObject ro = JsonConvert.DeserializeObject<RootObject>(json);

Answer 3

如果您只是想在不创建自定义C＃对象的情况下解析JSON，则可以使用JObject.Parse。

string json = "{\n\t\"ClassName\": \"Excel\",\n\t\"Teacher\": \"Esther\",\n\t\"Student\": 50,\n\t\"Aircond\": 0,\n\t\"Assets\": {\n\t\t\"Chair\": 50,\n\t\t\"Table\": 50,\n\t\t\"Fan\": 2,\n\t\t\"More\": \"randomText\"\n\t}\n}";
var jObject = JObject.Parse(json);
Console.WriteLine(jObject["Assets"]["More"]);

您将需要可以从NuGet安装的Newtonsoft.Json。