有没有人知道这个偶然的PHP任务的C#等价物:
Convert dot syntax like "this.that.other" to multi-dimensional array in PHP
也就是说,将像level1.level2.level3 = item
这样的字符串列表转换为字典或多维数组?
我假设字典需要保存object
类型的项目,之后我会将它们转换为Dictionary<string, string>
或string
,如果它是&#39;最后一项。
答案 0 :(得分:0)
这样的代码有用吗?
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Text.RegularExpressions;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string input = "level1.level2.level3 = item";
string pattern = "^(?'keys'[^=]+)=(?'value'.*)";
Match match = Regex.Match(input, pattern);
string value = match.Groups["value"].Value.Trim();
string[] keys = match.Groups["keys"].Value.Trim().Split(new char[] {'.'}, StringSplitOptions.RemoveEmptyEntries);
Dictionary<string, List<string>> dict = new Dictionary<string, List<string>>();
foreach (string key in keys)
{
if (dict.ContainsKey("key"))
{
dict[key].Add(value);
}
else
{
dict.Add(key, new List<string>() { value });
}
}
}
}
}
答案 1 :(得分:0)
我想你可以这样做,但是(我确定可以做更多的优化)
using System;
using System.Collections.Generic;
public class Program
{
public class IndexedTree {
private readonly IDictionary<string, IndexedTree> _me;
private object _value;
private readonly string _splitKey = ".";
public IndexedTree this[string key] {
get {
return _me[key];
}
}
public object Value { get; set; }
public void Add(string dottedItem) {
if ( string.IsNullOrWhiteSpace( dottedItem ) ) {
throw new ArgumentException("dottedItem cannot be empty");
}
int index;
if ( (index = dottedItem.IndexOf( _splitKey ) ) < 0 ) {
throw new ArgumentException("dottedItem didn't contain " + _splitKey);
}
string key = dottedItem.Substring(0, index), rest = dottedItem.Substring(index + 1);
IndexedTree child;
if (_me.ContainsKey(key)) {
child = _me[key];
} else {
child = new IndexedTree( _splitKey );
_me.Add(key, child);
}
if (rest.IndexOf(_splitKey) >= 0) {
child.Add(rest);
} else {
// maybe it can be checked if there is already a value set here or not
// in case there is a warning or error might be more appropriate
child.Value = rest;
}
}
public IndexedTree(string splitKey) {
_splitKey = splitKey;
_me = new Dictionary<string, IndexedTree>();
}
}
public static void Main()
{
IndexedTree tree = new IndexedTree(".");
tree.Add("Level1.Level2.Level3.Item");
tree.Add("Level1.Level2.Value");
Console.WriteLine(tree["Level1"]["Level2"].Value);
Console.WriteLine(tree["Level1"]["Level2"]["Level3"].Value);
}
}
你可以在这里看到结果: https://dotnetfiddle.net/EGagoz