Question

我已经尝试了StackOverflow上列出的几个不同的脚本，它们都会出现同样的错误。我知道记录存在于数据库中。请帮忙或解答。

我试过最新的脚本： -

<?php
$team='West Ham';
$query = "SELECT * from analysed where team = '$team'";
$result = mysql_query($query);

if(mysql_num_rows($result) > 0)
{
    echo " exists";
} else {
    echo " Dont exists";
}
?>

我甚至尝试过

$query = "SELECT * from analysed where 1d = '1'";

和

$query = "SELECT * from analysed where 1d = 1";

并得到相同的错误

警告：mysql_num_rows（）要求参数1为resource，boolean 在C：\ Program Files中给出第14行的（x86）\ EasyPHP-5.3.8.1 \ www \ football \ test-update.php

Answer 1

我不知道餐桌结构。我说不完美。您可以通过

查看问题

mysql_query($query) or die(mysql_error());

Answer 2

您可以使用此代码段作为示例：

<?php

 //CONNECT FIRST
$DB_SERVER = "dbhost";
$DB_USER = "dbuser";
$DB_PASSWORD = "dbpass";
$DB_NAME = "database";

$conn = new mysqli($DB_SERVER, $DB_USER, $DB_PASSWORD, $DB_NAME);

if ($conn->connect_error) {
      die("Connection failed." . $conn->connect_error);
}

$user_name = "Radu Radu";
$query = "SELECT * from users where user_name='$user_name'";
$result = $conn->query($query);

if ($result->num_rows > 0) {
        echo "User exist!";
} else {


   echo "User does not exist!";
}

Answer 3

期待您已经有数据库连接。

<?php
$team='West Ham';
$query=mysql_query("SELECT * from analysed WHERE team ='$team'");
$result = mysql_query($query);

$return_no_of_rows=mysql_num_rows($result);
if($return_no_of_rows>0)
{
 echo "Return Atleast one row";
}
else
{
 echo "Return Nothing";
 die();
}

＆GT;

我无法得到一个简单的PHP脚本来检查mysql中是否存在记录

3 个答案: