如何在“查询”构建器中向我的选择中添加自定义列?

时间:2016-09-05 09:33:13

标签: php sql symfony doctrine-orm query-builder

我有一个函数从表中选择一些列,使用QueryBuilder,我想在结果查询中添加一个自定义列。

像这样

SELECT u.id, "paid" as type FROM users as u WHERE u.deleted_at IS NOT NULL

这就是我所拥有的:

    /**
 * {@inheritdoc}
 */
public function getPaidOrderAnalytics(
    Agents $agent,    
    ParamFetcher $paramFetcher,
    $dateFrom,
    $dateTo
)
{
    $qb = $this->getEntityManager()->createQueryBuilder();
    $qb
        ->select('
             DISTINCT(o.id) as _id,
             o.createdAt as order_created_at,
             o.publicCost as public_cost,
             o.orderStatus as order_status,
             srv.services as service_name
        ')
        ->addSelect('
             "paid" as type

        ')
        ->from('ArtelProfileBundle:Orders', 'o')
        ->leftJoin('o.services', 'srv')
        ->leftJoin('o.leadService', 'ls')
        ->leftJoin('ls.lead', 'l')
        ->andWhere('l.agent = :agent')
        ->setParameter(':agent', $agent)
        ->orderBy('o.' . $paramFetcher->get('sort_by'), $paramFetcher->get('sort_order'))
        ->setFirstResult($paramFetcher->get('count') * ($paramFetcher->get('page') - 1))
        ->setMaxResults($paramFetcher->get('count'));

    $query = $qb->getQuery();
    $results = $query->getResult();

    return $results;
}

有错误

[Syntax Error] line 0, col 270: Error: Expected IdentificationVariable | ScalarExpression | AggregateExpression | FunctionDeclaration | PartialObjectExpression | "(" Subselect ")" | CaseExpression, got '"'

如何在“查询”构建器中的选择中添加自定义列?

2 个答案:

答案 0 :(得分:2)

尝试更改此内容:

[DataContract]
public class Demo : DynamicObject
{
 // This property is ignore in api response
 [DataMember]   OR [JsonProperty]
 public int Prop1 {get; set;}
}

使用:

        ->addSelect('
         "paid" as type

    ')

我成功转储了值作为示例

        ->addSelect('
         \'paid\' as type

    ')

希望这个帮助

答案 1 :(得分:-1)

试试这样:

$qb = $this->createQueryBuilder('e');
$qb->select('e')
   ->addSelect('e.paid as HIDDEN paid')