Question

在我的应用中，我想从字符串中删除除字符a-z之外的数字。我怎样才能获得角色？

Answer 1

这是一个简短的答案，不需要任何冗长的编码

NSString *newString = [[tempstr componentsSeparatedByCharactersInSet:
                            [[NSCharacterSet letterCharacterSet] invertedSet]] componentsJoinedByString:@""];`

迅捷3：

(tempstr.components(separatedBy:NSCharacterSet.letters.inverted)).joined(separator: "")

例如：

("abc123".components(separatedBy:NSCharacterSet.letters.inverted)).joined(separator: "")

Answer 2

NSString *stringToFilter = @"filter-me";


    NSMutableString *targetString = [NSMutableString string];


    //set of characters which are required in the string......
    NSCharacterSet *okCharacterSet = [NSCharacterSet characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyz"];


    for(int i = 0; i < [stringToFilter length]; i++)
    {
        unichar currentChar = [stringToFilter characterAtIndex:i];
        if([okCharacterSet characterIsMember:currentChar]) 
        {
            [targetString appendFormat:@"%C", currentChar];
        }
    }


    NSLog(targetString);    


    [super viewDidLoad];
}

这是给我的答案并且工作正常

Answer 3

我找到了答案：来自remove-all-but-numbers-from-nsstring

NSString *originalString = @"(123) 123123 abc";

NSLog(@"%@", originalString);
NSMutableString *strippedString = [NSMutableString 
                                   stringWithCapacity:originalString.length];

NSScanner *scanner = [NSScanner scannerWithString:originalString];
NSCharacterSet *numbers = [NSCharacterSet 
                           characterSetWithCharactersInString:@"abcdefghijklmnopqrstuvwxyz"];

while ([scanner isAtEnd] == NO) {
    NSString *buffer;
    if ([scanner scanCharactersFromSet:numbers intoString:&buffer]) {
        [strippedString appendString:buffer];

    } else {
        [scanner setScanLocation:([scanner scanLocation] + 1)];
    }
}

NSLog(@"%@", strippedString);

iphone sdk - 从字符串中删除除字符a-z之外的所有数字

3 个答案: