Question

我的ajax代码如下，它不是成功函数

function saveRecord() {
    $.ajax({
        url: "admin.aspx/inserData",
        type: "POST",
        dataType: 'text',

        data: JSON.stringify({
            "name": $("#name").val(),
            "uName": $("#uname").val(),
            "password": $("#pwd").val(),
            "adminType": $("#seAdmin").val(),
            "serviceArea": $("#selServiceArea").val(),
        }),
        contentType: "application/json; charset=utf-8",
        async: false,
        Success: FnInsertSuccess,

        Error: FnInsertError,
    });
}

和FnInsertSuccess就在这里

function FnInsertSucces(result) {
    alert(result.d);
        if (result.d == "Success") {
            console.log("data inserted");
            // $("#tblData tbody").append("<tr style='cursor:pointer'><td>" + $("#name").val() + "</td><td>" + $("#selServiceArea").val() + "</td><td>" + $("#seAdmin").val() + "</dt><td><a class='fa fa-pencil'></a><a class='fa fa-times' onclick='FnDeleteRow(this)'></a></td></tr>");
        }
        else if (result.d == "Fail") {
            alert("Not Successfully Insert");
        }

    }

Answer 1

嗨使用如下成功通话。它会起作用。

$.ajax({
url:"Where u need to go",
data: //data to send  
success:function(data) {
  alert(data); // data will be having the stuff that gets returned from the servlet.
}
complete: //here call ur fninsert function. This will work after the ajax     call is completed.

}）;

Answer 2

function saveRecord() {
$.ajax({
    url: "admin.aspx/inserData",
    type: "POST",
    dataType: 'text',

    data: JSON.stringify({
        "name": $("#name").val(),
        "uName": $("#uname").val(),
        "password": $("#pwd").val(),
        "adminType": $("#seAdmin").val(),
        "serviceArea": $("#selServiceArea").val(),
    }),
    contentType: "application/json; charset=utf-8",
    async: false,
    success: function(result){
        FnInsertSuccess(result)
     },

    error: function(data){
      FnInsertError(data);
    }
});

}

Answer 3

function saveRecord() {
  var name =  $("#name").val(),
  var uName = $("#uname").val(),
  var password =  $("#pwd").val(),
  var adminType =  $("#seAdmin").val(),
  var serviceArea =  $("#selServiceArea").val(),
$.ajax({
    url: "admin.aspx/inserData",
    type: "POST",
    dataType: 'JSON',

    data: {
        name: name,
        uName: uName,
        password: password,
        adminType: adminType,
        serviceArea: serviceArea
    },
    success:function(data){
     FnInsertSucces(data);
    }
});
}

- ＆GT;试试这个

我有ajax调用插入。数据被插入，但它没有成功

3 个答案: