Question

有几个R数据帧具有相同的两列：＆＃34; YMD＆＃34;，＆＃34; Amount＆＃34;如下

a <- data.frame(YMD = as.Date(c("2012-02-01", "2014-03-04", "2015-05-08")), Amount = c(100, 200, 300))
b <- data.frame(YMD = as.Date(c("2012-02-01", "2013-11-08", "2016-09-01")), Amount = c(10, 20, 30))
c <- data.frame(YMD = as.Date(c("2013-04-10", "2013-11-08", "2016-09-01")), Amount = c(1, 2, 3))

> a
         YMD Amount
1 2012-02-01    100
2 2014-03-04    200
3 2015-05-08    300

> b
         YMD Amount
1 2012-02-01     10
2 2013-11-08     20
3 2016-09-01     30

> c
         YMD Amount
1 2013-04-10      1
2 2013-11-08      2
3 2016-09-01      3

请教我如何在上述3个数据框中应用某种附加功能时获得以下结果

         YMD Amount
1 2012-02-01    110
2 2013-11-08     22
3 2014-03-04    200
4 2015-05-08    300
5 2016-09-01     33

谢谢！

Answer 1

我们可以在import spacy from nltk import Tree en_nlp = spacy.loads('en') doc = en_nlp("The quick brown fox jumps over the lazy dog.") def to_nltk_tree(node): if node.n_lefts + node.n_rights > 0: return Tree(node.orth_, [to_nltk_tree(child) for child in node.children]) else: return node.orth_ [to_nltk_tree(sent.root).pretty_print() for sent in doc.sents]中放置'data.frame'之后使用rbindlist中的data.table，然后按'YMD'分组，我们得到list'量'

sum

或使用library(data.table) rbindlist(list(a,b,c))[, .(Amount = sum(Amount)), by = YMD] # YMD Amount #1: 2012-02-01 110 #2: 2014-03-04 200 #3: 2015-05-08 300 #4: 2013-11-08 22 #5: 2016-09-01 33 #6: 2013-04-10 1，我们可以对dplyr和bind_rows

执行相同操作

summarise

Answer 2

我会做这样的事情：

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使用公共日期索引列添加来自不同数据帧的数字列

2 个答案: