Question

如何将功能舍入到最近的15分钟，而不是向下舍入？如果它的10:46它会圆到11:00

代码：

 var now = new Date();
    var Minutes = now.getMinutes();
    var quarterHours = Math.round(Minutes/15);
    if (quarterHours == 4)
    {
        now.setHours(now.getHours()+1);
    }
    var rounded = (quarterHours*15)%60;
    now.setMinutes(rounded);
    now.setSeconds(0);
    now.setMilliseconds(0);


    console.log(now.getTime());


    var currentdate = new Date(now.getTime()); 
    var datetime = "Last Sync: " + currentdate.getDate() + "/"
                    + (currentdate.getMonth()+1)  + "/" 
                    + currentdate.getFullYear() + " @ "  
                    + currentdate.getHours() + ":"  
                    + currentdate.getMinutes() + ":" 
                    + currentdate.getSeconds();


    console.log(datetime);

Answer 1

这个怎么样：

new Date(Math.ceil(new Date().getTime()/900000)*900000);

说明：new Date().getTime()以unix时间戳的形式（即自1970-01-01 00:00 UTC以来的毫秒数）返回当前时间，我们向上舍入到最近的900000的倍数（即Math.ceil的帮助下，即一小时一小时内的毫秒数。

修改：如果您要将其应用于15分钟以外的时间间隔，则可以这样做（例如30分钟）：

var interval = 30 * 60 * 1000; // 30 minutes in milliseconds
new Date(Math.ceil(new Date().getTime()/interval)*interval);

Answer 2

以毫秒为单位传递任意周期，以获取下一个周期示例2,4,8小时

function calculateNextCycle(interval) {
    const timeStampCurrentOrOldDate = Date.now();
    const timeStampStartOfDay = new Date().setHours(0, 0, 0, 0);
    const timeDiff = timeStampCurrentOrOldDate - timeStampStartOfDay;
    const mod = Math.ceil(timeDiff / interval);
    return new Date(timeStampStartOfDay + (mod * interval));
}

console.log(calculateNextCycle(4 * 60 * 60 * 1000)); // 4 hours in milliseconds

使功能四舍五入到最近的四分之一小时

2 个答案: