Question

我有LinkedList Queue，我正在尝试读取一个文件，其中包含等待帮助的队列中的人数以及当时可用于帮助的代理数量。我不知道要检查他们是否正忙，或者首先如何添加排队等候的人。谁能帮我？这是我到目前为止的代码。

public class WaitingQueue 
{
 public int [] windows = 0; // every time we add some one  check if location occupied
 public int time = 0;
  public int waitTime = 0;

 public static void main(String args[])
  {
   Queue newQueue = new Queue();
   try{

     FileInputStream fn = new FileInputStream(args[0]); 
     BufferedReader br = new BufferedReader(new InputStreamReader(fn));
     String line;

     while((line = br.readLine()) != null)
     {
         time++; // happens every time window i busy
         waitTime++  // increment waiTime
           if ( time for people to arrive)
         {
           add people to the queue // have to have a queue for people waiting.
             //use enque to add people.
         }
         if(window is open)
         {
           // move people from queue to window
           // use dequeue
         }

         if(time = x;)
         {
           // add some people to list
         }
       }

  //Close the input stream
       outFile.close();
       fn.close();
      }
     }catch (Exception e)
     {/*Catches exception*/
      System.err.println("An error has occured : " + e.getMessage());
      }
     }

Answer 1

<强> - 编辑 -

我看到您的代码现在已经用Java标记了;我的代码更像是一个c＃/ pseudo，所以你可能需要把它转换成Java。

<强> - 编辑 -

虽然这可能没有帮助。但我建议采用更加实体化的方法;类似的东西：

代理商，代理商列表：应列出可用的代理商
客户，客户队列：应保留一组需要帮助的客户
客户支持经理：
- 应该查看代理是否可用（不忙）
- Dequeue客户
- 将其分配给其中一个可用座席

在我的头顶上方，请参阅以下内容：

<强>客户：

public class Customer
{
    string _strName;
    public Customer(string strName) { _strName = strName; }
}

<强>代理：

public class Agent
{
    string _strName;
    bool _bIsBusy = false;//
    public bool IsBusy { get { return _bIsBusy; } }

    Customer _Customer;
    public Agent(string strName)
    {
        _strName = strName;
    }

    public void HandleCustomer(Customer theCustomer)
    {
        _Customer = theCustomer;
        _bIsBusy = true;//Busy as long as the window is open.

        //You might need something that doesnt block;
        Thread.Sleep(5 * 1000); //Wait for time to simulate that agent is talking to customer

        RemoveCustomer();//Done with the customer.
    }

    private void RemoveCustomer()
    {
        _Customer = null;
        _bIsBusy = false;
    }
}

<强>管理器：

根据可用性管理客户和代理的类

public class CustomerServiceBench
{
    Queue<Customer> queCustomers = new Queue<Customer>();
    List<Agent> lstAgents = new List<Agent>();
    Thread thdService;

    public CustomerServiceBench()
    {
        //Something along these lines.
        thdService = new Thread(delegate() { WaitAndAddCustomerIfAgentIsAvailable(); });

    }

    private void AddCustomer()
    {
        //Add a dummy customer.
        Random r = new Random(1231);
        queCustomers.Enqueue(new Customer("Customer" + r.Next().ToString()));

        Thread.Sleep(5 * 1000); //SpinWait.Once()...

    }

    private void WaitAndAddCustomerIfAgentIsAvailable()
    {
        //Thread1 to manage the 

    }
}

Answer 2

这不是微不足道的，所以我建议您搜索一下有大量示例代码的教程，然后根据您的需要进行修改。

8.3 The Producer/Consumer Pattern - Java Threads, Third Edition

The producer-consumer pattern in Java 5: using blocking queues in preference to wait()/notify()

LinkedList队列实现

2 个答案: