我想创建一个XSL样式表来转换xml，其中的元素按文本排序。
来源xml：
<package>
<name>awesome-name</name>
<version>1.0.6</version>
<description>
here is description
</description>
<maintainer email="foo@bar.com">Jon S.</maintainer>
<maintainer email="aaa@bbb.com">George A.</maintainer>
<license>BSD</license>
<url>http://aaa.bbb.com/</url>
<buildtool_depend>aaaaaaa</buildtool_depend>
<!-- build depend -->
<build_depend>aaaa</build_depend>
<build_depend>dddd</build_depend>
<build_depend>bbbb</build_depend>
<build_depend>cccc</build_depend>
<!-- run depend -->
<run_depend>aaaa</run_depend>
<run_depend>dddd</run_depend>
<run_depend>cccc</run_depend>
<run_depend>bbbb</run_depend>
<export>
<foo bar="aaa"></foo>
</export>
<!-- large
footer
comment -->
</package>
预期输出xml（*_depend按字母顺序排序，其他元素只是通过）：
<package>
<name>awesome-name</name>
<version>1.0.6</version>
<description>
here is description
</description>
<maintainer email="foo@bar.com">Jon S.</maintainer>
<maintainer email="aaa@bbb.com">George A.</maintainer>
<license>BSD</license>
<url>http://aaa.bbb.com/</url>
<buildtool_depend>aaaaaaa</buildtool_depend>
<!-- build depend -->
<build_depend>aaaa</build_depend>
<build_depend>bbbb</build_depend>
<build_depend>cccc</build_depend>
<build_depend>dddd</build_depend>
<!-- run depend -->
<run_depend>aaaa</run_depend>
<run_depend>bbbb</run_depend>
<run_depend>cccc</run_depend>
<run_depend>dddd</run_depend>
<export>
<foo bar="aaa"></foo>
</export>
<!-- large
footer
comment -->
</package>
但输出是：
<package>
<name>awesome-name</name>
<version>1.0.6</version>
<description>
here is description
</description>
<maintainer email="foo@bar.com">Jon S.</maintainer>
<maintainer email="aaa@bbb.com">George A.</maintainer>
<license>BSD</license>
<url>http://aaa.bbb.com/</url>
<buildtool_depend>aaaaaaa</buildtool_depend>
<build_depend>aaaa</build_depend>
<build_depend>dddd</build_depend>
<build_depend>bbbb</build_depend>
<build_depend>cccc</build_depend>
<run_depend>aaaa</run_depend>
<run_depend>dddd</run_depend>
<run_depend>cccc</run_depend>
<run_depend>bbbb</run_depend>
<export>
<foo/>
</export>
</package>
此处，注释已删除，导出的内部元素（foo）未正确传递。
我创建的XSL样式表如下：
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:preserve-space elements="description export"/>
<xsl:template match="*">
<xsl:element name="{name()}">
<xsl:apply-templates select="node()|@*" />
</xsl:element>
</xsl:template>
<xsl:template match="@*|comment()">
<xsl:copy-of select="." />
</xsl:template>
<xsl:template match="/package">
<xsl:copy>
<xsl:copy-of select="*[self::name]" />
<xsl:copy-of select="*[self::version]" />
<xsl:copy-of select="*[self::description]" />
<xsl:copy-of select="*[self::maintainer]" />
<xsl:copy-of select="*[self::license]" />
<xsl:copy-of select="*[self::url]" />
<xsl:copy-of select="*[self::author]" />
<xsl:copy-of select="*[self::buildtool_depend]" />
<xsl:copy-of select="*[self::buildtool_export_depend]" />
<xsl:for-each select="build_depend">
<xsl:sort data-type="string" />
<xsl:copy-of select="." />
</xsl:for-each>
<xsl:for-each select="run_depend" >
<xsl:sort data-type="string" />
<xsl:copy-of select="." />
</xsl:for-each>
<xsl:for-each select="exec_depend" >
<xsl:sort data-type="string" />
<xsl:copy-of select="." />
</xsl:for-each>
<xsl:for-each select="test_depend">
<xsl:sort data-type="string" />
<xsl:copy-of select="." />
</xsl:for-each>
<xsl:for-each select="doc_depend">
<xsl:sort data-type="string" />
<xsl:copy-of select="." />
</xsl:for-each>
<xsl:for-each select="conflict">
<xsl:sort data-type="string" />
<xsl:copy-of select="." />
</xsl:for-each>
<xsl:for-each select="replace">
<xsl:sort data-type="string" />
<xsl:copy-of select="." />
</xsl:for-each>
<xsl:copy-of select="*[self::export]" />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
我的样式表或更好的解决方案有什么问题？
答案 0 :(得分：0)
这是你可以看到它的一种方式：
XSLT 1.0
<div class="gallery__wrapper">
<div class="image-main__wrapper">
<img class="image-main" src="https://unsplash.it/g/1000/400?image=0">
<div id="arrows">
<i class='material-icons left-btn'>chevron_left</i>
<i class='material-icons right-btn'>chevron_right</i>
</div>
<div class="image-thumbnails__wrapper">
<ul class="thumbnails">
<li><img id="thumb-1" class="gallery__img" src="https://unsplash.it/g/150/100?image=1"></li>
<li><img id="thumb-2" class="gallery__img" src="https://unsplash.it/g/150/100?image=2"></li>
<li><img id="thumb-3" class="gallery__img" src="https://unsplash.it/g/150/100?image=3"></li>
<li><img id="thumb-4" class="gallery__img" src="https://unsplash.it/g/150/100?image=4"></li>
<li><img id="thumb-5" class="gallery__img" src="https://unsplash.it/g/150/100?image=5"></li>
<li><img id="thumb-6" class="gallery__img" src="https://unsplash.it/g/150/100?image=6"></li>
<li><img id="thumb-7" class="gallery__img" src="https://unsplash.it/g/150/100?image=7"></li>
<li><img id="thumb-8" class="gallery__img" src="https://unsplash.it/g/150/100?image=8"></li>
</ul>
</div>
</div>
</div>
然而，这仍然相当尴尬，必须列出所有可能的元素名称。请考虑改为Muenchian grouping：
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/package">
<xsl:copy>
<xsl:apply-templates select="node()[not(contains(name(), '_depend'))]
| buildtool_depend[1]
| build_depend[1]
| run_depend[1]"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[contains(name(), '_depend')]">
<xsl:for-each select="../*[name()=name(current())]" >
<xsl:sort/>
<xsl:copy-of select="." />
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>