我运行这个sql代码:
SELECT @rownum := @rownum + 1 AS position,
user_id, score, user_type
FROM users_data
ORDER BY score DESC
结果如下:
我有2个像这样的用户的表
我的桌子
users1
+----+----------+----------+
| id | username | position |
+----+----------+----------+
| 1 | uname | 0 |
| 2 | uname2 | 0 |
| 3 | uname3 | 0 |
| 5 | uname5 | 0 |
| 11 | uanme11 | 0 |
| 12 | uname12 | 0 |
+----+----------+----------+
users0
+-----+----------+----------+
| id | username | position |
+-----+----------+----------+
| 1 | uname | 0 |
| 111 | uname111 | 0 |
| 138 | uname138 | 0 |
| 241 | uname241 | 0 |
+-----+----------+----------+
我希望在一个查询中运行SELECT sql时更新用户位置。
if user_type is 0, update users0.position = @rownum
if user_type is 1, update users1.position = @rownum
结果必须是这样的:
users1
+----+----------+----------+
| id | username | position |
+----+----------+----------+
| 1 | uname | 1100 |
| 2 | uname2 | 1100 |
| 3 | uname3 | 1075 |
| 5 | uname5 | 1075 |
| 11 | uanme11 | 1075 |
| 12 | uname12 | 1175 |
+----+----------+----------+
users0
+-----+----------+----------+
| id | username | position |
+-----+----------+----------+
| 1 | uname | 1075 |
| 111 | uname111 | 1025 |
| 138 | uname138 | 1025 |
| 241 | uname241 | 1025 |
+-----+----------+----------+
答案 0 :(得分:1)
while ($line = <INFILE>) {
结果
update users1,users0
set users1.position = (
select v.position
from
(SELECT
@rn1 := @rn1 + 1 AS position,
users_id, score, user_type
FROM (select @rn1:=0) rn, users_data ud
ORDER BY score DESC
) v
where v.users_id = users1.id and v.user_type = 1
)
,
users0.position = (
select s.position
from
(SELECT
@rn := @rn + 1 AS position,
users_id, score, user_type
FROM (select @rn:=0) rn, users_data ud
ORDER BY score DESC
) s
where s.users_id = users0.id and s.user_type = 0
)
where 1 = 1
;