我想学习在Go中编程,我决定作为一个宠物程序,我会为几个CommandHandler做一个不同命令的简单调度程序(如果CommandHandler与它应该处理的命令同名。)
我的问题是当我想要一个CommandHandlerManager发布一个将被调度到正确的CommandHandler的命令时,它告诉我我需要有一个具体的HelloWorldCommand实现,因为HelloWorldCommandHandler没有实现Command的接口
编译时出现错误消息
E:\Desktop\ManBear\golang\src>go run main.go
# command-line-arguments
.\main.go:71: cannot use cmdHandler (type HelloWorldCommandHandler) as type CommandHandler in array or slice literal:
HelloWorldCommandHandler does not implement CommandHandler (wrong type for Handle method)
have Handle(HelloWorldCommand)
want Handle(Command)
我需要有人向我解释我做错了什么,我猜这意味着我应该单独为我的HelloWorldCommandHandler实现一个单独的 func 方法,如下所示:
func (ch HelloWorldCommandHandler) Handle(cmd Command) {
fmt.Println("HelloWorldCommandHandler handled the basic command with name --> " + cmd.GetName())
}
但它创造了更多与类型相关的错误。
我正在尝试解释如何以及为什么我做错了,这是一个很好的例子。
谢谢。
这是我的代码:
package main
import (
"fmt"
"strconv"
)
type Command interface {
GetName() string
}
type CommandHandler interface {
Command
Handle(cmd Command)
}
type HelloWorldCommand struct {
Command
Name string
Age int
}
func (cmd HelloWorldCommand) GetName() string {
return "HelloWorldCommand"
}
type HelloWorldCommandHandler struct {
CommandHandler
}
func (cmd HelloWorldCommandHandler) GetName() string {
return "HelloWorldCommand"
}
func (ch HelloWorldCommandHandler) Handle(cmd HelloWorldCommand) {
fmt.Println("Hello World! My name is " + cmd.Name + " and I'm " + strconv.Itoa(cmd.Age) + " years old!")
}
type CommandHandlerManager struct {
CommandHandlers []CommandHandler
}
func (chm CommandHandlerManager) Publish(cmd Command) {
for _, cmdHandler := range chm.CommandHandlers {
if cmd.GetName() == cmdHandler.GetName() {
cmdHandler.Handle(cmd)
}
}
}
func main() {
fmt.Println("Hey my friend!")
cmd := HelloWorldCommand {Name: "ManBear", Age: 357}
cmdHandler := HelloWorldCommandHandler {}
fmt.Println(cmd.GetName())
fmt.Println(cmdHandler.GetName())
cmdHandler.Handle(cmd)
cmdHandlerManager := CommandHandlerManager {
CommandHandlers: []CommandHandler {
cmdHandler, // <-- the error is here
},
};
}
更新:
对于好奇,这是我的宠物程序的功能版本
感谢 Dean Elbaz 的帮助,建议使用类型断言,它可以通过正确的CommandHandler处理命令,并使用每个Command附带的正确值集。
package main
import (
"fmt"
"strconv"
"time"
)
type Command interface {
GetName() string
}
type CommandHandler interface {
Command
Handle(cmd Command)
}
const HelloWorldCommandName string = "HelloWorldCommand"
type HelloWorldCommand struct {
Command
Name string
Age int
}
func (cmd HelloWorldCommand) GetName() string {
return HelloWorldCommandName
}
// Basic Hello World
type HelloWorldCommandHandler struct {
CommandHandler
}
func (cmd HelloWorldCommandHandler) GetName() string {
return HelloWorldCommandName
}
func (ch HelloWorldCommandHandler) Handle(cmd Command) {
fmt.Println("Hello World!\n----------------------------------------\n")
}
// Hello World with Name and Age
type HelloWorldWithNameAndAgeCommandHandler struct {
CommandHandler
}
func (cmd HelloWorldWithNameAndAgeCommandHandler) GetName() string {
return HelloWorldCommandName
}
func (ch HelloWorldWithNameAndAgeCommandHandler) Handle(cmd Command) {
var helloWorldCommand HelloWorldCommand = cmd.(HelloWorldCommand)
fmt.Println("Hello World! My name is " + helloWorldCommand.Name + " and I'm " + strconv.Itoa(helloWorldCommand.Age) + " years old!\n----------------------------------------\n")
}
const TodayDateTimeCommandName string = "TodayDateTimeCommand"
// Today's DateTime Command
type TodayDateTimeCommand struct {
Command
TimeZone string
}
func (cmd TodayDateTimeCommand) GetName() string {
return TodayDateTimeCommandName
}
type TodayDateTimeCommandHandler struct {
}
func (ch TodayDateTimeCommandHandler) GetName() string {
return TodayDateTimeCommandName
}
func (ch TodayDateTimeCommandHandler) Handle(cmd Command) {
var todayCommand TodayDateTimeCommand = cmd.(TodayDateTimeCommand)
location, err := time.LoadLocation(todayCommand.TimeZone)
if err != nil {
fmt.Errorf("Could not load the Location of the TimeZone. %f", err.Error())
return
}
current_time := time.Now().In(location)
fmt.Println("Today's date and time is " + current_time.String() + " for the time zone: " + todayCommand.TimeZone)
}
// The CommandHandler Manager
type CommandHandlerManager struct {
CommandHandlers []CommandHandler
}
func (chm CommandHandlerManager) Publish(cmd Command) {
for _, cmdHandler := range chm.CommandHandlers {
if cmd.GetName() == cmdHandler.GetName() {
cmdHandler.Handle(cmd)
}
}
}
func main() {
fmt.Println("Hey my friend!\n\n\n")
cmdHandlerManager := CommandHandlerManager {
CommandHandlers: []CommandHandler {
HelloWorldCommandHandler {},
HelloWorldWithNameAndAgeCommandHandler {},
TodayDateTimeCommandHandler {},
},
};
cmd := HelloWorldCommand {Name: "ManBear", Age: 357}
cmdHandlerManager.Publish(cmd)
fmt.Println("~~~~~~~~ other command published ~~~~~~~~~~~~~~~~~~~~~")
cmd2 := TodayDateTimeCommand{ TimeZone: "America/Montreal" }
cmdHandlerManager.Publish(cmd2)
}
答案 0 :(得分:1)
Handle
的签名必须完全func (ch HelloWorldCommandHandler) Handle(cmd Command) {
才能实现该接口。
快速解决方法是在Handle
函数的开头执行type assertion以从HelloWorldCommand
获取Command
但我认为这可能是一个可能的设计问题的症状:如果多态性在Command
上,那么命令应该处理/运行自己?可能在界面中有Run() error
吗?