Question

我有一张桌子pa_acc_status，我附上了桌子的图像。

我想比较2个日期（一个是用户输入，另一个是列值），它将使用MYSQL在循环中从一列遍历到另一列。

例如：首先它将检查step_22_due_date列是否为空并且step_22_due_date＆lt; = USER_DATE，如果这是真的，则退出该行并继续下一行否则对step_21_complete执行相同操作，然后执行step_21_due_date，然后执行step_1_complete

即step_22_due_date - ＆gt; step_21_complete - ＆gt; step_21_due_date - ＆gt; step_1_complete

我想以两种方式输出

案例1：适用于USER_DATE = 2016-09-03

首先喜欢这个

id | step_1_complete | step_21_due_date | step_21_complete | step_22_due_date | user_id
1  |      NULL       | 2016-03-12       | NULL             | NULL             | 1
2  |      NULL       | 2016-03-12       | NULL             | NULL             | 1
3  |      NULL       |      NULL        |      NULL        | 2016-04-15       | 2
4  |      NULL       | 2016-03-12       | NULL             | NULL             | 2
5  |      NULL       |      NULL        | 2016-03-12       | NULL             | 2

第二个是日期的计数，它不是空的group by user_id

step_1_complete | step_21_due_date | step_21_complete | step_22_due_date | user_id
0          |  2         |  0         |  0         | 1
0          |  1         |  1         |  1         | 2

案例2：适用于USER_DATE = 2016-03-10

首先喜欢这个

id | step_1_complete | step_21_due_date | step_21_complete | step_22_due_date | user_id
1  |      2016-03-08 | NULL             | NULL             | NULL             | 1
2  |      2016-03-08 | NULL             | NULL             | NULL             | 1
3  |      2016-03-08 | NULL             | NULL             | NULL             | 2
4  |      2016-01-03 | NULL             | NULL             | NULL             | 2
5  | NULL            | 2016-03-08       | NULL             | NULL             | 2

第二个是日期的计数，它不是空的group by user_id

step_1_complete | step_21_due_date | step_21_complete | step_22_due_date | user_id
2          |  0         |  0         |  0         | 1
2          |  1         |  0         |  0         | 2

我不知道是否可以使用MySQL，任何帮助或建议都会有所帮助。

Answer 1

最后，我得到了解决方案，我的问题，

对于数据列表

SET @USER_DATE = '2016-03-08';

SELECT *
FROM
  (SELECT `id`,
          `user_id`,
          `step_1_complete`,
          NULL AS `step_21_due_date`,
          NULL AS `step_21_complete`,
          NULL AS `step_22_due_date`
   FROM `pf_acc_status`
   WHERE `step_1_complete` IS NOT NULL
     AND `step_1_complete` <= @USER_DATE
     AND (`step_21_due_date` IS NULL
          OR step_21_due_date >= @USER_DATE)
   UNION ALL SELECT `id`,
                    `user_id`,
                    NULL AS `step_1_complete`,
                    `step_21_due_date`,
                    NULL AS `step_21_complete`,
                    NULL AS `step_22_due_date`
   FROM `pf_acc_status`
   WHERE `step_21_due_date` IS NOT NULL
     AND `step_21_due_date` <= @USER_DATE
     AND (`step_21_complete` IS NULL
          OR step_21_complete >= @USER_DATE)
   UNION ALL SELECT `id`,
                    `user_id`,
                    NULL AS `step_1_complete`,
                    NULL AS `step_21_due_date`,
                    `step_21_complete`,
                    NULL AS `step_22_due_date`
   FROM `pf_acc_status`
   WHERE `step_21_complete` IS NOT NULL
     AND `step_21_complete` <= @USER_DATE
     AND (`step_22_due_date` IS NULL
          OR step_22_due_date >= @USER_DATE)
   UNION ALL SELECT `id`,
                    `user_id`,
                    NULL AS `step_1_complete`,
                    NULL AS `step_21_due_date`,
                    NULL AS `step_21_complete`,
                    `step_22_due_date`
   FROM `pf_acc_status`
   WHERE `step_22_due_date` IS NOT NULL
     AND `step_22_due_date` <= @USER_DATE ) AS `a`
ORDER BY a.`id` ASC

适用于count数据

SET @USER_DATE = '2016-03-08';

SELECT a.`user_id`,
       count(a.`step_1_complete`) AS step_1_complete,
       count(a.`step_21_due_date`) AS step_21_due_date,
       count(a.`step_21_complete`) AS step_21_complete,
       count(a.`step_22_due_date`) AS step_22_due_date
FROM
  (SELECT `id`,
          `user_id`,
          `step_1_complete`,
          NULL AS `step_21_due_date`,
          NULL AS `step_21_complete`,
          NULL AS `step_22_due_date`
   FROM `pf_acc_status`
   WHERE `step_1_complete` IS NOT NULL
     AND `step_1_complete` <= @USER_DATE
     AND (`step_21_due_date` IS NULL
          OR step_21_due_date >= @USER_DATE)
   UNION ALL SELECT `id`,
                    `user_id`,
                    NULL AS `step_1_complete`,
                    `step_21_due_date`,
                    NULL AS `step_21_complete`,
                    NULL AS `step_22_due_date`
   FROM `pf_acc_status`
   WHERE `step_21_due_date` IS NOT NULL
     AND `step_21_due_date` <= @USER_DATE
     AND (`step_21_complete` IS NULL
          OR step_21_complete >= @USER_DATE)
   UNION ALL SELECT `id`,
                    `user_id`,
                    NULL AS `step_1_complete`,
                    NULL AS `step_21_due_date`,
                    `step_21_complete`,
                    NULL AS `step_22_due_date`
   FROM `pf_acc_status`
   WHERE `step_21_complete` IS NOT NULL
     AND `step_21_complete` <= @USER_DATE
     AND (`step_22_due_date` IS NULL
          OR step_22_due_date >= @USER_DATE)
   UNION ALL SELECT `id`,
                    `user_id`,
                    NULL AS `step_1_complete`,
                    NULL AS `step_21_due_date`,
                    NULL AS `step_21_complete`,
                    `step_22_due_date`
   FROM `pf_acc_status`
   WHERE `step_22_due_date` IS NOT NULL
     AND `step_22_due_date` <= @USER_DATE ) AS `a`
GROUP BY a.`user_id`
ORDER BY a.`id` ASC

MySQL查询比较两个日期，它将从一列遍历到另一列

1 个答案: