一个基本问题 - >因为很多天以来我找不到答案
如果我有for loop
(10次)并且每个输出是不同的string
。如何制作特定的String-output
彩色?
for(int i=0; i< posts.length();i++ ) {
JSONObject post = posts.optJSONObject(i);
this.title = post.optString("title");
blogTitles[i] = title;
}
当然,我可以按代码
对特定的blogtitles[i]
进行排序
title.toLowerCase().contains("neune")
但是如果我尝试给它新layout
,他layout
用于所有(10x)输出
任何可以帮忙?
现在回答我改为
JSONObject post = posts.getJSONObject(i);
this.title = post.getString("title");
但仍然所有输出都是黑色和布局&#34; android.R.layout.simple_list_item_1&#34;
完整代码
for(int i=0; i< posts.length();i++ ) {
JSONObject post = posts.getJSONObject(i);
this.title = post.getString("title");
arrayAdapter1 = new ArrayAdapter(MainActivity.this, R.layout.mytextview, blogTitles1);
arrayAdapter2 = new ArrayAdapter(MainActivity.this, android.R.layout.simple_list_item_1, blogTitles2);
if (title.toLowerCase().contains("neune") && title.contains(this.id.toLowerCase())) { //ean nicht neu (!kontrolliert!)
// listView.setTheme(R.layout.mytextview);
listView.setAdapter(arrayAdapter1);
String title2= title.replace("neune*", "");
String title3 = title2.replace(this.id + ",", "-eigene Bewertung");
blogTitles1[i] = title3;
bewertungseingabe.setVisibility(View.VISIBLE);
bewertungsueberschrift.setVisibility(View.VISIBLE);
bewertbutton.setVisibility(View.VISIBLE);
editBtn.setVisibility(View.VISIBLE);
}
if (title.toLowerCase().contains("neune") ) {
listView.setAdapter(arrayAdapter2);
String title2= title.replace("neune*", "error!!!!");
String title3 = title2.replace(this.id + ",", "*");
blogTitles2[i] = title3;
}
if (title.toLowerCase().contains("neuja")&& title.contains(this.id.toLowerCase())) { //ean neu (!noch nicht kontrolliert!)
String title2= title.replace("neuja*", "");
String title3 = title2.replace(this.id + ",", "-eigene Bewertung");
blogTitles1[i] = title3;
}
if (title.toLowerCase().contains("neuja") ) {
blogTitles2[i] = "Dieser Artikel ist in Ordnung!";
}
if (title.toLowerCase().contains("ganz")) { //ean neu (!noch nicht kontrolliert!)
blogTitles2[i] = "Du hast uns so eben eine neue EAN mitgeteilt" +
"füge eine Bezeichnung und Bewertung hinzu, wenn du magst...";
// zaehler[i]=blogTitles[i];
}
}
只使用了第二种布局....我想这是因为&#34; title.toLowerCase()。包含(&#34; neune&#34;)&amp;&amp; title.contains(this.id.toLowerCase())&#34;是真的&#34; title.toLowerCase()。包含(&#34; neune&#34;)&#34;是真的......它必须&#34;这样,因为应评估每个(i)输出
答案 0 :(得分:0)
按如下方式解析Json
。
JSONObject post = posts.getJSONObject(i);
this.title = post.getString("title");
答案 1 :(得分:0)
修改强>
String getStr;
for(int i=0; i< posts.length();i++ ) {
JSONObject post = posts.optJSONObject(i);
this.title = post.optString("title");
blogTitles[i] = title;
getStr = blogTitles[i];
if("neune".equals(getStr)){
SpannableStringBuilder builder = new SpannableStringBuilder();
SpannableString redSpannable= new SpannableString(getStr);
redSpannable.setSpan(new ForegroundColorSpan(Color.RED), 0, getStr, 0);
builder.append(redSpannable);
}