Question

Country.php

<?php

namespace app\models;

use yii\db\ActiveRecord;

class Country extends ActiveRecord
{
}

现在我使用上面的类使用默认的db配置

来查询Country表

use app\models\Country;

// get all rows from the country table and order them by "name"
$countries = Country::find()->orderBy('name')->all(); // this line uses default db configuration

保护/配置/ main.php

return array(
    'components' => array(
            'db' => require(dirname(__FILE__).'/../../db_config.php'),
            'dba' => require(dirname(__FILE__).'/../../dba_config.php'),
            'dbmobisite' => require(dirname(__FILE__).'/../../dbmobisite_config.php'),
            'dbamobisite' => require(dirname(__FILE__).'/../../dbamobisite_config.php'),
    )
)

现在我改变了：

$db = Yii::app()->getComponent('dbmobisite'); //wanted to use different db
$db->setActive(true); //changing it to active
$countries = Country::find()->orderBy('name')->all(); //but this still queries using "db" configuration not "dbmobisite" configuration.

我想＆＃34; dbmobisite＆＃34;仅适用于单个查询。可能吗？如果可能请帮助我。

提前致谢

Answer 1

我认为最简单的解决方案是创建一个由此扩展的新类并覆盖getDb（）方法，例如：

<?php

namespace app\models;

use yii\db\ActiveRecord;

class CountryOtherDb extends Country
{
      public function getDb()
      {
             return \Yii::$app->otherDb
      }
}

Yii：使用activerecord时如何为特定查询使用不同的数据库

1 个答案: