Question

在switch语句中对数组进行过滤的正确方法是什么

let filteredMachines = (filterTerm,filterField) => {
       switch (filterField) {
       case 'NomAppareil':this.props.machines.filter(machine => {
           return machine.nomAppareil === filterTerm;
       });
       break;

       case 'CodeAppareil':this.props.machines.filter(machine => {
           return machine.codeAppareil === filterTerm;
       });
       break;

       case 'NomClient':this.props.machines.filter(machine => {
           return machine.nomClient === filterTerm;
       });
       break;

       case 'CodeClient':this.props.machines.filter(machine => {
            console.log('inside CodeClient ='+JSON.stringify(machine));
           return (machine.codeClient == filterTerm);
       });
       break;

       case 'NoSerie':this.props.machines.filter(machine => {
           return machine.noSerie === filterTerm;
       });
       break;

       default: return this.props.machines;
     }
   };

编辑：我找到了下面给出的工作解决方案

let filteredMachines = machines.filter((machine) =>{
     switch (filterField) {
     case 'NomAppareil':  return machine.nomAppareil === filterTerm;
     case 'CodeAppareil': return machine.codeAppareil === filterTerm;
     case 'NomClient': return machine.nomClient === filterTerm;
     case 'CodeClient': return machine.codeClient === filterTerm;
     case 'NoSerie': return machine.noSerie === filterTerm;
           default: return true;
   }

}）;

Answer 1

基本上你需要返回已过滤的数组（因此undefined结果），然后你可以省略break语句。

case 'NomAppareil':
    return this.props.machines.filter(machine => {
//  ^^^^^^
       return machine.nomAppareil === filterTerm;
    });
    // break;

或使用Set代替switch声明。

let filteredMachines = (filterTerm, filterField) => {
    var set = new Set(['NomAppareil', 'CodeAppareil', 'NomClient', 'CodeClient', 'NoSerie']);
    return set.has(filterField) ? 
        this.props.machines.filter(machine => machine[filterField] === filterTerm) :
        this.props.machines;
};

Answer 2

您可以执行以下操作;

var filters = ["NomAppareil","CodeAppareil","NomClient","CodeClient","NoSerie"],
     result = filters.indexOf(filterField) !== -1 ? this.props.machines.filter(machine => machine[filterField] === filterTerm)
                                                  : this.props.machines;

Javascript在switch语句中返回过滤后的数组

2 个答案: