Question

为什么此代码不显示颜色

function doFirst(){
  var x= document.getElementById('canvas');
  canvas=x.getContext('2d');
  var g=canvas.createLinearGradient(0,0,100,100);
  g.addColorStop(.0,"blue");
  g.addColorStop(1,"red");
  canvas.fillstyle=g;
  canvas.fillRect(0,0,100,100);
}
window.addEventListener("load", doFirst, false);

Answer 1

您的代码中有拼写错误，应该有$client = new \GuzzleHttp\Client(); $response = $client->request('GET', $request_url, [ 'headers' => ['Accept' => 'application/xml'], 'timeout' => 120 ])->getBody()->getContents(); $responseXml = simplexml_load_string($response); if ($responseXml instanceof \SimpleXMLElement) { $key_value = (string)$responseXml->key_name; }而不是canvas.fillStyle。

＆＃13;

canvas.fillstyle

＆＃13;

function doFirst(){
  var x = document.getElementById('canvas');
  canvas = x.getContext('2d');
  var g = canvas.createLinearGradient(0,0,100,100);
  g.addColorStop(.0,"blue");
  g.addColorStop(1,"red");
  canvas.fillStyle = g;
  canvas.fillRect(0,0,100,100);
}

window.addEventListener("load", doFirst, false);

＆＃13;

希望这有帮助！

Answer 2

它奏效了。现在为什么这不起作用： `function doFirst（）{ var x = document.getElementById（'canvas'）; canvas = x.getContext（'2d'）;

canvas.shadowOffsetX = 4;
canvas.shadowOffsetY = 4;
canvas.shadowBlur = 6;
canvas.shadowColor='rgba(0,0,255,.5)';

canvas.font="bold 3px Tahoma";
canvas.textAlign="end";
canvas.fillText("ongwtfbbq",300,100);

} window.addEventListener（“load”，doFirst，false）;`

javascript的颜色不适用于chrome

2 个答案: