Question

我从特定架构中删除一行时收到此错误：

Hibernate: select journal0_.id as id1_2_0_, journal0_.content as content2_2_0_, journal0_.filename as filename3_2_0_, journal0_.subject as subject4_2_0_, journal0_.tags as tags5_2_0_, journal0_.user_id as user_id6_2_0_, journal0_.version as version7_2_0_ from journal journal0_ where journal0_.id=?
Hibernate: select nextval ('hibernate_sequence')
Hibernate: insert into subscription (journal_id, user_id, version, id) values (?, ?, ?, ?)
2016-09-03 01:08:01.581  WARN 13462 --- [nio-8080-exec-9] o.h.engine.jdbc.spi.SqlExceptionHelper   : SQL Error: 23505, SQLState: 23505
2016-09-03 01:08:01.581 ERROR 13462 --- [nio-8080-exec-9] o.h.engine.jdbc.spi.SqlExceptionHelper   : Unique index or primary key violation: "UK_9XFQUT5UKXNSBX8NL2LR23TC5_INDEX_9 ON PUBLIC.SUBSCRIPTION(USER_ID, JOURNAL_ID) VALUES (9, 2, 10)"; SQL statement:
insert into subscription (journal_id, user_id, version, id) values (?, ?, ?, ?) [23505-191]
2016-09-03 01:08:01.598  INFO 13462 --- [nio-8080-exec-9] o.h.e.j.b.internal.AbstractBatchImpl     : HHH000010: On release of batch it still contained JDBC statements
2016-09-03 01:08:01.632 ERROR 13462 --- [nio-8080-exec-9] c.j.exceptions.ErrorController           : Exception during execution of SpringSecurity application

org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement

即使调用了带有正确参数的delete方法，它仍然会运行导致数据冲突问题的插入查询。

以下是模型：

@Entity
@Table(uniqueConstraints={@UniqueConstraint(columnNames={"userId", "journalId"})})
public class Subscription {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id;

    @Version
    private Integer version;

    private Integer userId;
    private Integer journalId;

    public void setId(Integer id) {
        this.id = id;
    }

    public Integer getId() {
        return this.id;
    }

    public void setVersion(Integer version) {
        this.version = version;
    }

    public Integer getVersion() {
        return this.version;
    }

    public void setUserId(Integer userId) {
        this.userId = userId;
    }

    public Integer getUserId() {
        return this.userId;
    }

    public void setJournalId(Integer journalId) {
        this.journalId = journalId;
    }

    public Integer getJournalId() {
        return this.journalId;
    }
}

这是调用delete方法的地方：

@Override
public void unsubscribeJournalForSubscriber(Journal journal, Account subscriber) {

    Subscription subscription = new Subscription();
    subscription.setJournalId(journal.getId());
    subscription.setUserId(subscriber.getId());


    this.subscriptionRepository.delete(subscription);
}

Answer 1

要删除Subscription实体，您只需要设置实体的主键，即Subscription Entity的id字段。但是，您要设置journalId和userId字段并尝试删除。您应该只设置订阅实体的id字段，它将被删除。

<强>更新

您的存储库代码应为

public interface SubscriptionRepository extends CrudRepository<Subscription, Integer> {

    /**
     * Returns array of Subscribed journals by specific user's id
     * 
     * @param userId
     * @return
     */
    ArrayList<Subscription> findByUserId(Integer userId);
    List<Subscription> findByUserIdAndJournalId(Integer userId, Integer journalId);

}

现在您的商家登录代码将是：

@Override
public void unsubscribeJournalForSubscriber(Journal journal, Account subscriber) {

    List<Subscription> list = subscriptionRepository.findByUserIdAndJournalId(subscriber.getId(), journal.getId());

    for(Subscription subscription : list){
        subscriptionRepository.delete(subscription);
    }

}

Answer 2

如果要删除记录而不使用主键，请为此创建一个查询。在“ SubscriptionRepository”中创建一个名为

的方法

@Modifying @Query("delete from Subscription s where s.role. userId = ?1 and s. journalId = ?2") deleteByUserIdJournalId(Integer userId,Integer journalId)，然后使用该方法删除您的记录。遵循此https://docs.spring.io/spring-data/jpa/docs/current/reference/html/

无法执行声明; SQL [不适用];约束[null];

2 个答案: