preg_match与第一个实例

Question

我试图在＆＃34;＆＃34;之间抓住一个单词。和＃34;与＆＃34;在一个字符串里面。问题是我有另一个＆＃34;＆＃34;的实例，它将扩展通配符。

以下是一个例子：

$item   = 'This is a car in red with new tires and with a radio';
$pattern =  = '/in (.*) with/i';
preg_match($pattern, $item, $matches);

返回：

array(2) {
  [0]=>
  string(30) "in red with new tires and with"
  [1]=>
  string(22) "red with new tires and"
}

我希望$ match [1]是＆＃39; red＆＃39;

Answer 1

将您的模式更改为：

templateUrl

$pattern = '/in ([^\s]*)(.*) with/i'; // Array ( [0] => in red with new tires and with [1] => red [2] => with new tires and ) 的含义 - 取所有不是([^\s]*)的符号。