I have a order list with about 10 list items that have anchor tag links associated with them. I am trying to force the user to only be able to click the child of the parent li once the link is visited. So in a sense I want to force the user to click the li links in the sequential order that is generated by the ol.
Here is my html:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>titlePage</title>
<link rel="stylesheet" type="text/css" href="titlePage.css"></head>
<script src="../jsLibraries/jquery-3.1.0.js"></script>
<script src="titlePage.js"></script>
</head>
<body>
<img id="backgroundIMG" src="images/Chapter-v2.png">
<ol id="chapterNumbers">
<li><a href="../chapters/chapter0.html">Chapter 0 - Animate Content</a></li>
<li><a href="../chapters/chapter1.html">Chapter 1 - Animate Content 2</a></li>
<li><a href="../chapters/chapter2.html">Chapter 2 - Video Content</a></li>
<li><a href="../chapters/chapter3.html">Chapter 3 - Video Content 2</a></li>
<li><a href="../chapters/chapter4.html">Chapter 4 - Audio Content</a></li>
<li><a href="../chapters/chapter5.html">Chapter 5 - Blah</a></li>
<li><a href="../chapters/chapter6.html">Chapter 6 - Blah</a></li>
<li><a href="../chapters/chapter7.html">Chapter 7 - Blah</a></li>
<li><a href="../chapters/chapter8.html">Chapter 8 - Blah</a></li>
<li><a href="../chapters/exam.html">Exam</a></li>
</ol>
<header id="courseTitle"> 001234OOELNA - Example Course Using Adobe Animate </header>
</body>
</html>
Here is my jQuery JS that I was starting with:
$(document).ready(function(){
$("li").first().nextAll().click(function( event ) {
event.preventDefault();
});
});
Here is the CSS associated with the anchor tag being visited:
a:visited {
color:white;
}
Here is a link to the out put as it is:
http://skywest.theyard.space/index/titlePage.html
任何人都可以帮我弄清楚我出错的地方以及如何做到这一点,一旦第一个链接被点击,第一个孩子的链接被激活(返回true?)等等,所以用户必须点击按顺序链接?
谢谢! 埃里克
答案 0 :(得分:2)
如果用户点击链接,导航出链接页面,那么任何技巧 使用添加/删除类将无法正常工作。
因此,即使在返回带有链接的页面后,此代码也可以正常工作。 关闭/打开浏览器后重新下载订单。
$(document).ready( function() {
if (!sessionStorage.active) {
sessionStorage.active = "1";
}
(function set() {
$("li a").each(function(idx, elm) {
if (sessionStorage.active != idx+1) {
$(elm)
.parent().fadeTo(1, 0.7)
.off("click").on("click", function(evt) {
evt.preventDefault();
});
} else {
$(elm)
.parent().fadeTo(500, 1)
.off("click").on("click", function() {
sessionStorage.active = parseInt(sessionStorage.active, 10) + 1;
set();
});
}
});
}());
});
第2版:
$(document).ready( function() {
if (!localStorage.active) {
localStorage.active = "1";
}
(function set() {
$("li a").each(function(idx, elm) {
if (localStorage.active < idx+1) {
$(elm)
.parent().fadeTo(1, 0.7)
.off("click").on("click", function(evt) {
evt.preventDefault();
});
} else if (localStorage.active == idx+1){
$(elm)
.parent().fadeTo(1000, 1)
.off("click").on("click", function() {
localStorage.active = parseInt(localStorage.active, 10) + 1;
set();
});
} else if (localStorage.active > idx+1) {
$(elm)
.parent().fadeTo(1000, 1)
.off("click").on("click", function() {
return true;
});
}
});
}());
});
或版本2超级“smplfd”,部分灵感来自jefré-n代码
$(function(){var a=localStorage.a||0,l=$('a')
l.click(function(){if(l.index(this)>a)return false
if(l.index(this)==a)localStorage.a=++a})})
答案 1 :(得分:1)
检查一下。 (我很好地评论我的代码,所以不需要解释。但是,如果你需要澄清,请告诉我......:D)
try:
tweet = json.loads(line)
except Exception as err:
print err # or use log to see what happen
else:
tweets_data.append(tweet)
错误摘要:
我最初处理“更新”var $links = $("li a");
//simplify localStorage error checking
var supportsLS = true;
try {
//this will throw an exception if we can't use localStorage
//ie. the user, like me, disables cookies ... :)
localStorage.supportsLocalStorage = true;
}
catch (exc) {
supportsLS = false;
}
//initialize the first link they can use
if (supportsLS && localStorage.getItem("nextAvail") === null) {
localStorage.nextAvail = 0;
}
function onLinkClick (evt) {
/*
This handles a given click on a link.
*/
//no point in running rest of code--they don't have localStorage support
//OR we aren't allowed to use it
if (supportsLS === false) {
return;
}
//cache some info -- improve readability
var thisInd = $links.index(this);
var nextAvail = parseInt(localStorage.nextAvail);
//they can't view this link -- prevent it from working
if (thisInd > nextAvail) {
evt.preventDefault();
}
//if they clicked the last link they're allowed to click,
//update localStorage.nextAvail so they can click the next link.
else if (thisInd === nextAvail) {
localStorage.nextAvail = thisInd + 1;
}
}
//setup onclick handlers
$links.click(onLinkClick);
的方式是有缺陷的 普通错误。您可以检查代码以查看原因,但只需说“更新”没有更新,并且在以预期方式使用程序时,用户可能会意外撤消其进度。
答案 2 :(得分:0)
你的JS会创建所有链接,但第一个不可点击,无论他们是否被访问过。
很遗憾,您无法根据js确定是否访问了某个链接(请参阅this link)。