Question

我已经在python中创建了一个web scraper但是在最后打印时我想要打印（＆＃34; Bakerloo：＆＃34; + info_from_website）我已经下载了，你可以在代码中看到，但它总是就像info_from_website一样出现并忽略＆＃34; Bakerloo：＆＃34;串。无论如何都无法解决它。

import urllib
import urllib.request
from bs4 import BeautifulSoup
import sys

url = 'https://tfl.gov.uk/tube-dlr-overground/status/'
page = urllib.request.urlopen(url)
soup = BeautifulSoup(page,"html.parser")

try:
   bakerlooInfo = (soup.find('li',{"class":"rainbow-list-item bakerloo "}).find_all('span')[2].text)
except:
   bakerlooInfo = (soup.find('li',{"class":"rainbow-list-item bakerloo disrupted expandable "}).find_all('span')[2].text)

bakerloo = bakerlooInfo.replace('\n','')
print("Bakerloo     : " + bakerloo)

Answer 1

我会使用CSS selector来获取disruption-summary类的元素：

import requests
from bs4 import BeautifulSoup

url = 'https://tfl.gov.uk/tube-dlr-overground/status/'
page = requests.get(url)
soup = BeautifulSoup(page.content, "html.parser")

service = soup.select_one('li.bakerloo .disruption-summary').get_text(strip=True)
print("Bakerloo: " + service)

打印：

Bakerloo: Good service

（在这里使用requests）。

请注意，如果您只想列出具有中断摘要的所有电台，请执行以下操作：

import requests
from bs4 import BeautifulSoup

url = 'https://tfl.gov.uk/tube-dlr-overground/status/'
page = requests.get(url)
soup = BeautifulSoup(page.content, "html.parser")

for station in soup.select("#rainbow-list-tube-dlr-overground-tflrail-tram ul li"):
    station_name = station.select_one(".service-name").get_text(strip=True)
    service_info = station.select_one(".disruption-summary").get_text(strip=True)

    print(station_name + ": " + service_info)

打印：

Bakerloo: Good service
Central: Good service
Circle: Good service
District: Good service
Hammersmith & City: Good service
Jubilee: Good service
Metropolitan: Good service
Northern: Good service
Piccadilly: Good service
Victoria: Good service
Waterloo & City: Good service
London Overground: Good service
TfL Rail: Good service
DLR: Good service
Tram: Good service

Python Web Scraper打印问题

1 个答案: